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lidiya [134]
2 years ago
5

What is the explicit formula for this sequence? −7, −4, −1, 2, 5, …

Mathematics
1 answer:
VikaD [51]2 years ago
7 0

The explicit formula for the sequence is 3n -10

<h3>What is an Arithmetic Sequence ?</h3>

An arithmetic sequence is a series of terms which have  common difference between its consecutive numbers.

The sequence given is

−7, −4, −1, 2, 5, …

The common difference between each term is d =3

-4-(-7) = 3

-1-(-4) =3

The nth term for a sequence is given by

\rm T_n =  a +(n-1)d

Here a is the first term = -7

n is the no. of terms  = n

d is the common difference = 3

Therefore the equation will be

\rm T _n = -7 + (n-1) * 3

\rm T _n = -7 +3n -3

\rm T _n = 3n -10

Therefore the explicit formula for the sequence is 3n -10 .

To know more about Arithmetic Sequence

brainly.com/question/15412619

#SPJ1

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Please help!! x = 2 - 3 cos t, y = 1 + 4 sin t in rectangular form?<br><br> thank you! :)
sukhopar [10]

Answer:

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

Step-by-step explanation:

x=2-3\cos(t)

y=1+4\sin(t)

Let's solve for \cos(t) in the first equation and then solve for \sin(t) in the second equation.

I will then use the following identity to get right of the parameter, t:

\cos^2(t)+\sin^2(t)=1 (Pythagorean Identity).

Let's begin with x=2-3\cos(t).

Subtract 2 on both sides:

x-2=-3\cos(t)

Divide both sides by -3:

\frac{x-2}{-3}=\cos(t)

Now time for the second equation, y=1+4\sin(t).

Subtract 1 on both sides:

y-1=4\sin(t)

Divide both sides by 4:

\frac{y-1}{4}=\sin(t)

Now let's plug it into our Pythagorean Identity:

\cos^2(t)+\sin^2(t)=1

\frac{x-2}{-3})^2+(\frac{y-1}{4})^2=1

\frac{(x-2)^2}{(-3)^2}+\frac{(y-1)^2}{4^2}=1

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

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Answer:

Step-by-step explanation:

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