Answer: for me the best option is D.
Explanation: lets explain this.
Cellular respiration begins with a process that divides the glucose within the cells making it readily available as a source of energy. This process can occur without oxygen (anaerobic respiration) or in the presence of oxygen (aerobic respiration). Anaerobic respiration generates more excess waste (lactate) than aerobic . Besides, high levels of lactate build within the muscle cells. Excess lactate slows the cellular respiratory process and is experienced as a burning sensation in the muscles if exercise continues.
Explanation:
algea bottom of foodchain with water worms and mice?
Answer:
The ATP and NADPH from light reaction serve as an energy source and reducing power respectively during the Calvin cycle, which is also called the dark phase of photosynthesis.
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Answer:
Point mutations are a broad category of mutations that describe a change in a single nucleotide of DNA, such as a substitution for another nucleotide, deletion of a nucleotide, or insertion of a single nucleotide into the DNA, resulting in DNA that differs from the normal or wild type gene...
or you can say:
Point mutations are a large category of mutations that describe a change in single nucleotide of DNA, such that that nucleotide is switched for another nucleotide, or that nucleotide is deleted, or a single nucleotide is inserted into the DNA that causes that DNA to be different from the normal or wild type gene ...
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>