(x+b/2a)^2-(b^2-4ac)/2a=0
Step 2:
Re-write the expression:
(x+b/2a)^2=(b^2-4ac)/4a^2
Step 3:
get the square root of both sides:
x+b/2a=sqrt[(b^2-4ac)/4a^2]
Step 4:
Simplifying we get:
x+b/2a=sqrt[b^2-4ac]/2a
Step 5
Make x the subject:
x=-b/2a+/-sqrt[b^2-4ac]/2a
1/26
In a standard pack of 52 playing cards there are 2 black 6 's
The 6 of spades and the 6 of clubs
Probability = number of favourable outcomes / number of possible outcomes
P( black 6 ) =2/52 = 1/26 in simplest form
Answer:
2y+15
Step-by-step explanation:
y+(15+y)
y+15+y
(y+y)+15
2y+15
Answer:
The area of the shaded region is 
Step-by-step explanation:
we know that
The area of the shaded region is equal to the area of the sector of circle of angle 68.9 degrees minus the area of the isosceles triangle
step 1
Find the area of sector of the circle
The area of circle is equal to

assume


substitute


Remember that the area of a circle subtends a central angle of 360 degrees
so
using proportion Find out the area of a sector with a central angle of 68.90 degrees
Let
x -----> the area of a sector

step 2
Find the area of the isosceles triangle
Applying the law of sines
The area is equal to

we have

substitute

step 3
Find the area of the shaded region

Round to the nearest tenth

Answer:
K = (2v)/2
Step-by-step explanation:
1. Multiply both sides by 2/n
<u>Now: (2v)/n = b + K</u>
<u></u>
2. Subtract k from both sides
<u>Now: (2v)/n - b = K</u>