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xxMikexx [17]
3 years ago
9

How much would $600 invested at 8% interest compounded continuously be

Mathematics
1 answer:
sattari [20]3 years ago
7 0
Give me a min I’m solving hmmm if you round it to the nearest cent you get
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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

6 0
3 years ago
Round to the nearest whole number of degrees. Enter only a whole number.
quester [9]

Answer:

22 degrees

Step-by-step explanation:

using inverse tangent

2.1/5.3 = 0.396226415

tan -1(0.396226415

ANSWER = 21.6147

8 0
3 years ago
Read 2 more answers
Arrange these numbers in order from least to greatest 0.1, 1, -1,
LenaWriter [7]

Answer:

-1, 0.1, 1

•••••••••••••

3 0
3 years ago
Read 2 more answers
Find the value of 151 - 4(32 - 2).<br> -11<br> -33<br> 7<br> -23
egoroff_w [7]

Steps to solve:

151 - 4(32 - 2)

~Distribute

151 - 128 - 8

~Subtract

23 - 8

15

Best of Luck!

3 0
3 years ago
4(4x−8)+4(3x−7)=7(2x+5)+6]\<br><br><br> I NEED HELP FAST!!!!
Deffense [45]

The answer you are looking for is 7\frac{101}{14}.



Explanation:

4(4x−8)+4(3x−7)=7(2x+5)+6

Step 1: Simplify both sides of the equation.

4(4x−8)+4(3x−7)=7(2x+5)+6

(4)(4x)+(4)(−8)+(4)(3x)+(4)(−7)=(7)(2x)+(7)(5)+6(Distribute)

16x+−32+12x+−28=14x+35+6

(16x+12x)+(−32+−28)=(14x)+(35+6)(Combine Like Terms)

28x+−60=14x+41

28x−60=14x+41

Step 2: Subtract 14x from both sides.

28x−60−14x=14x+41−14x

14x−60=41

Step 3: Add 60 to both sides.

14x−60+60=41+60

14x=101

Step 4: Divide both sides by 14.

14x

14

=

101

14

x=

101

14


3 0
3 years ago
Read 2 more answers
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