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MissTica
3 years ago
14

Abe

Biology
1 answer:
Allushta [10]3 years ago
5 0

Answer:

i think the answer is A source

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Why do we conduct scientific investigations
valentina_108 [34]
In order to understand the world we are living in i guess
6 0
3 years ago
How does gravity affects the Earth's orbit around the Sun?
kiruha [24]

Answer:

The Sun's gravitational force is like the tetherball rope, in that it constantly pulls Earth toward it. ... This means that the planet neither flies out into space nor falls into the Sun. Instead, it travels in a nearly circular motion around the Sun, creating an orbit

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3 years ago
En una isla oceánica aislada hay una especie de pájaros, la
Zinaida [17]

Answer:

La frecuencia del alelo recesivo s es igual a 0.2 (opción b)

Explanation:

<u>Datos disponibles</u>:

  • Plumaje gris es el fenotipo dominante
  • Plumaje con manchas blancas es el fenotipo recesivo
  • S es el alelo dominante para plumaje gris
  • s es el alelo recesivo para plumaje manchado
  • Variedad manchada representa el 4% de la población.

Si ejemplares con ala manchada y genotipo ss representan el 4% de la población, entonces los restantes 96% corresponden a ejemplares grises homocigotas dominantes SS y heterocigotas Ss. Las frecuencias fenotípicas serán:

  • Plumaje gris (SS + Ss) = 96% = 0.96
  • Plumaje manchado (ss) = 4% = 0.04

De acuerdo al equilibrio de Hardy-Winberg, la suma de las frecuencias alélicas equivale a 1, y la suma de las frecuencias genotípicas también equivale a 1.

  • Frecuencia del alelo dominante = p
  • Frecuencia del alelo recesivo = q
  • Frecuencia de genotipo homocigota dominante = p²
  • Frecuencia de genotipo heterocigota = 2xpxq
  • Frecuencia del genotipo homocigota recesivo = q²

Entonces,

  • p + q = 1
  • p² + 2pq + q² = 1

Si la frecuencia genotípica del homocigota recesivo es 0.04, entonces la raíz cuadrada de ese valor es la frecuencia génica del alelo recesivo. Esto es:

  • q² = 0.04
  • q = √0.04 = 0.2

A partir de la ecuación p + q = 1, podemos calcular el valor de p.

p + q = 1

p + 0.2 = 1

p = 1 - 0.2

p = 0.8

Entonces la frecuencia genotípica del homocigota dominante es p²

p² = 0.8² = 0.64

Y la frecuencia genotípica del heterocigota es

2pq = 2 x p x q = 2 x 0.8 x 0.2 = 0.32

Para corroborar esto, la suma de todas las frecuencias genotípicas debe dar uno.

0.64 + 0.32 + 0.04 = 1

5 0
3 years ago
What occurs in the non living part of the water cycle?
DanielleElmas [232]
What occurs in the nonliving part of the water cycle? It seeps in the ground and becomes ground water. Water is taken by roots of plants after going through plants the water moves in the atmosphere. ... in the living portion of the water cycle, 
8 0
4 years ago
Help me with this please i will give 20 points because this is a lot
Colt1911 [192]

Answer:

causes a cell to change: hypotonic,hypertonic

doesnt change the shape of the cell: isotonic

I dont know what the 3rd one is

Causes a cell to shrink:Hypertonic

Explanation:

7 0
3 years ago
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