Question

Please help me it’s due today please help me please please people help me please please

Answer 1

Answer:

a) 0≠ -10

b) x= -3

c)y= 0

Step-by-step explanation:

a) 3-4x=-7-4x

$3-4x=-7-4x\\Adding \ 4x \ on \ both \ sides\\3-4x+4x=-7-4x+4x\\3-0=-7\\Adding \ -3\\3-0-3=-7-3\\0\neq -10$

So, this equation has no solution as both sides are not equal.

b) $15-2x=-7x$

Solving:

$15-2x=-7x\\Adding \ 2x \ on \ both \ sides\\15-2x+2x=-7x+2x\\15=-5x\\Divide \ both \ sides \ by -5\\x=-3$

So, this equation has one solution

c) 7(y-3)=6y-21

Solving:

$7(y-3)=6y-21\\7y-21=6y-21\\Adding \ -6y \ on \ both \ sides\\7y-21-6y=6y-21-6y\\y=-21+21\\y=0$

So, this equation has one solution.

1. Write equation with no solution. 3-4x=-7-4x (check solution of a)

2. Write equation with one solution. 7(y-3)=6y-21 (check solution of c)

3. Write equation with infinite solution. 2x + 3 = x + x + 3

solving:

2x+3=2x+3

2x-2x+3=3

3=3

When both sides are equal, the equation has infinite solutions.