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3 years ago

Given f(x) = 4x - 6, evaluate f(3). A. 2 B. 1 C.12 D. 6

Mathematics

1 answer:

Dima020 [189]3 years ago

7 0

Answer:

Step-by-step explanation:

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Which expression is equivalent to (8^2)^-4

xz_007 [3.2K]

Answer:

C: $\frac{1}{8*8*8*8*8*8*8*8}$

Step-by-step explanation:

$a^{-n} = \frac{1}{a^n}$

Since a = $8^2$ :

$(8^2)^{-n} = \frac{1}{(8^2)^n} =\frac{1}{8^{2n}}$

Since n = 4 :

$(8^2)^{-4} =\frac{1}{8^{2*4}}=\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}$

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2 years ago

Box plot i dont understand any thing about it

Inga [223]

Answer:

Just put the numbers in order then the interquartile range would be the largest number from the high quartile and the lowest number from the lower quartile.

5 0

3 years ago

Frank grows evergreen trees. He grew 535 trees for

TiliK225 [7]

Answer:

Frank grows 535 trees during holiday season
in November sold 215
then dec sold 275
535 minus 490 which gives a total of 45 trees left
then to find out how many trees he will have next season 650 plus 45 gives 695

3 0

2 years ago

45% of what number is 27?

gtnhenbr [62]

45% of what number is 27

0.45x = 27
x = 27 / 0.45
x = 60 <== 45% of 60 = 27

5 0

3 years ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

3 years ago