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3 years ago

Please help!!!!!!!!!!!!!! I need help please!!!!!!

Mathematics

2 answers:

serg [7]3 years ago

7 0

Answer:

It would be c

Step-by-step explanation:

Have a nice day!

julsineya [31]3 years ago

5 0

Answer:

Step-by-step explanation:

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I need some help with this one. Please give it a go! Thank you for your time!

LekaFEV [45]

Answer:

A) $3x^{2} - x - 4$

B) $-3x^{2} -4x -5$

Step-by-step explanation:

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3 years ago

18. QS bisects ZPQR. If mZPQS = 3x and

il63 [147K]

The answer is b because

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3 years ago

Use the distributive property to rewrite the expression –2(6 – x) without parentheses.

slava [35]

The correct answer is B

8 0

3 years ago

PLEASE HELP!! WILL GIVE BRAINLY!!!

alexgriva [62]

Answer:

x = 102 degrees

Step-by-step explanation:

Since the line is through parrallel lines, we know that angle 2 and angle 7 will be equal to each other, so all you have to do is set the equations equal to each other to solve.

2x-37 = x+65

Subtract x from the left to isolate the variable and add 37 to the right.

x = 102

7 0

3 years ago

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

4 0

3 years ago