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3 years ago

Please help!!!!!!!!!!!!!! I need help please!!!!!!

Mathematics

2 answers:

serg [7]3 years ago

7 0

Answer:

It would be c

Step-by-step explanation:

Have a nice day!

julsineya [31]3 years ago

5 0

Answer:

Step-by-step explanation:

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Find an example of a 2 dimensional object in your house that is rectangular or triangular.

Dmitry_Shevchenko [17]

Answer:

A = 216 cm^2

P = 80 cm

Step-by-step explanation:

l = 12

w = 18

As the object is rectangular, the area is height * width and the perimeter is

2(height + width) as there are two of each side.

12 * 18 = 216 U^2 U = unit of measurement, I would presume for a poster you use cm so its 216 cm^2

12 + 18 = 40

40 * 2 = 80 cm

6 0

3 years ago

Find the circumference of the circle with 1/4 Pi square centimetre square 2<br>

otez555 [7]

Answer:

The circumference of the circle is 6 cm (approximately).

Step-by-step explanation:

Given:

Area of the circle = 1/4π²

Now, to get the circumference of the circle we need the radius.

So, finding the radius by putting the formula of area:

Area = $\pi r^{2}$

$\frac{1}{4} \pi ^{2}$ = $\pi r^{2}$

dividing π by both sides:

$\frac{1}{4}\pi$ $=r^{2}$

using square root on both the sides:

$\frac{1}{2}\sqrt{\pi } = r$

So, the radius is $\frac{1}{2}\sqrt{\pi }$

Now, putting the formula of circumference:

$circumference=2\pi r$

= $2\pi\frac{1}{2} \sqrt{\pi}$

= $\pi \sqrt{\pi}$

putting the value of π =3.14

= $3.14\times\sqrt{3.14}$

= $3.14\times1.77$

= $5.56$

Circumference = 5.56 cm

Therefore, the circumference of the circle is 6 cm (approximately).

4 0

3 years ago

Hey again.. Please answer!!

Molodets [167]

Answer:

I can't see the question

its too small can you type it out?

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

In your biology class, your final grade is based on several things: a lab score, scores on two major tests, and your score on th

WARRIOR [948]

Answer:

$Weighted\ Average = 73$

Step-by-step explanation:

Given

$Lab = 21\%$

$Tests = 25\%$

$Exam = 29\%$

$Lab\ Score = 60$

$First\ Test = 81$

$Second\ Test = 69$

$Exam = 79$

Required

The weighted average

To do this, we simply multiply each score by the corresponding worth.

i.e.

$Weighted\ Average = Lab\ worth * Lab\ score + Tests\ worth * Tests\ score.....$

So, we have:

$Weighted\ Average = 21\% * 60 + 25\% * 81 + 25\% * 69 + 29\% * 79$

Using a calculator, we have:

$Weighted\ Average = 73.01$

$Weighted\ Average = 73$ --- approximated

4 0

3 years ago

A differential equation, a point, and a slope field are given. A slope field(or direction field) consists of line segments with

mihalych1998 [28]

Answer:

Step-by-step explanation:

We're gonna need a graph to do this one.

4 0

3 years ago