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Gwar [14]
2 years ago
13

Four more than twice a numbera.2x+4b.4x+2c.6xd.2x > 4​

Mathematics
1 answer:
makkiz [27]2 years ago
6 0

Answer:

a. 2x + 4

Step-by-step explanation:

Four more than twice a number

Let x = unknown number

Four more than twice of x

Twice of x can be written as 2x

Four more than 2x

Four more can be written as + 4

We get 2x + 4

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Prove the following statements: (a) For every integer x, if x is even, then for every integer y, xy is even. (b) For every integ
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Answer and Step-by-step explanation:

(a) Given that x and y is even, we want to prove that xy is also even.

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(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:

Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.

(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.

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