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larisa [96]
3 years ago
9

One lap around a track is ½ mile. It takes Bryan ⅛ hour to ride one lap. What is Bryan’s mile per hour?

Mathematics
1 answer:
Paul [167]3 years ago
7 0

Answer:

4 miles per hour

Step-by-step explanation:

Total miles = 1/2

Time taken = 1/8

Miles per hour = 1/2 ÷ 1/8

= 1/2 × 8/1

= 8/2

= 4 miles per hour

Bryan’s mile per hour = 4

4 miles per hour

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Find the y-intercept of the line that passes through the given point and has the given slope : (-2,-1); m=-3
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Answer:

0, -7

Step-by-step explanation:

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3 years ago
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Anna earned 22 points on her last test. If there were 40 possible points, what was her percent grade?
dimulka [17.4K]

Answer:

55%

Step-by-step explanation:

Since Anna earned 22 points, and there was a total of 40 points, this means that she scored 22 out of 40 points. You can simplify this by dividing the denominator and numerator by 2. Then, you can multiply both the numerator and denominator by 5 to get a number out of 100.

\frac{22}{40} = \frac{11}{20}=\frac{55}{100}*100%=55%

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3 years ago
A firework is launched at the rate of 10 feet per second from a point on the ground 50 feet from an observer. to 2 decimal place
Kazeer [188]

The rate of change of the angle of elevation when the firework is 40 feet above the ground is 0.12 radians/second.

First we will draw a right angle triangle ΔABC, where ∠B = 90°

Lets, assume the height(AB) = h and base(BC)= x

If the angle of elevation, ∠ACB = α, then

tan(α) = \frac{AB}{BC} = \frac{h}{x}

Taking inverse trigonometric function, α = tan⁻¹ (\frac{h}{x}) .............(1)

As we need to find the rate of change of the angle of elevation, so we will differentiate both sides of equation (1) with respect to time (t) :

\frac{d\alpha}{dt}=[\frac{1}{1+ \frac{h^2}{x^2}}]*(\frac{1}{x})\frac{dh}{dt}

Here, the firework is launched from point B at the rate of 10 feet/second and when it is 40 feet above the ground it reaches point A,

that means h = 40 feet and \frac{dh}{dt} = 10 feet/second.

C is the observer's position which is 50 feet away from the point B, so x = 50 feet.

\frac{d\alpha}{dt}= [\frac{1}{1+ \frac{40^2}{50^2}}] *\frac{1}{50} *10\\ \\ \frac{d\alpha}{dt} = [\frac{1}{1+\frac{16}{25}}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt} = [\frac{25}{41}] *\frac{1}{5}\\   \\ \frac{d\alpha}{dt}= \frac{5}{41} =0.1219512

= 0.12 (Rounding up to two decimal places)

So, the rate of change of the angle of elevation is 0.12 radians/second.

5 0
3 years ago
I will give brainliest if you answer this question !!!
yanalaym [24]

Answer:

A) 2

Step-by-step explanation:

Start off with the given information. The question states that the x-int. is 4, so you should recognize that there is a point at (4,0). Plug the point into the equation.

k(4) + 2(0) + 8 = 0

Now simplify the equation.

4k + 0 + 8 = 0

Isolate the variable, make sure it's on its own side.

4k = 8

Now get the k by itself to solve the equation. Divide both sides by 4.

k = 2

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What kinds of regular polygons can be used for regular tessellations? Check all that apply.
Fiesta28 [93]

Answer:

Step-by-step explanation:

The regular polygons that can be used to form a regular tessellation are an equilateral triangle, a square, and a regular hexagon.

Hope it helps

plz mark as brainliest!!!!!!

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