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3 years ago

The distance between two towns is 90 kilometers. there are approximately 8 kilometers in 5 miles

Mathematics

1 answer:

vitfil [10]3 years ago

4 0

Answer:

55.9234

Step-by-step explanation:

Distance between two towns is 90 kilometers.

8 kilometers = 5 miles

1 kilometers = 0.621371 miles

So:

90 kilometers = 55.9234 miles

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Which is the graph of linear inequality 6x+2y>-10

NemiM [27]

For this case we have the following inequality:
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(x, y)
The ordered pairs that meet the inequality, will be included as part of the graph.
Therefore, the shaded region contains all the ordered pairs that meet the inequality.
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3 years ago

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Dmitriy789 [7]

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3 years ago

What is the amount, base, and percent in the expression.

Illusion [34]

Answer:

The correct answer is :

Amount: 2

Base: 100

Percent: 2%

Step-by-step explanation:

So, we get the answer by using whatever we know. The first step is that 2 is the percent because it is having the percent sign . In addition we know that 100 is the base. And the one which is left is 2 so it's the amount.

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3 years ago

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otez555 [7]

Answer:

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6 0

2 years ago

Read 2 more answers

44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access

DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.

FileSystemLocked → ∀x Access(x, SystemMailbox)

(c)

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0

3 years ago

The distance between two towns is 90 kilometers. there are approximately 8 kilometers in 5 miles​

The distance between two towns is 90 kilometers. there are approximately 8 kilometers in 5 miles