You have the following function:
g(x) = 3x - 7
In order to determine th value of x when g(x) = -4, you equal the previous expression to -4 and solve for x, just as follow:
g(x) = 3x - 7 replace g(x) = -4
-4 = 3x - 7 add 7 both sides
-4 + 7 = 3x simplify
3 = 3x divide by 3 both sides
3/3 = x
x = 1
Hence, the anser is x = 1
Answer:
r≥0
V(r) ≥0
Step-by-step explanation:
V(r) = 4/3 * Pi* r^3
The domain is the input values for r
The radius cannot be less than 0 but can be any number bigger than 0
What is the domain of the function in this situation?
r≥0
The range is the output values for the function or the volume
The volume must be greater than or equal to zero
V(r) ≥0
When you divide two fractions, you do Keep, Change, Flip or KCF. So you keep the 3/5, you change the division sign to a multiplication sign, then flip the 3/15 to 15/3. So the new equation is 3/5x15/3. Then you simply the two sides so it becomes 1/1x3/1.....
Meaning the answer is 3.
