3 years ago

If XY=24, XZ=22, and JQ=5, find the radius of the circumscribed circle of triangle XYZ.

1 answer:

3 0

23 to the 3 because I just took it

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Alchen [17]

<u>ANSWER</u>

Only the equation is a function

<u>EXPLANATION</u>

$f(x)=x^2+8$ is graphed above with its inverse $f^{-1}(x)=\pm \sqrt{x-8}$ .

We perform the vertical line test for both the equation and its inverse.

The equation $f(x)=x^2+8$ passed the vertical line hence it is a function.

However, $f^{-1}(x)=\pm \sqrt{x-8}$ failed the vertical line test, hence it is not a function.

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3 years ago

lesantik [10]

Answer:

there is no picture... but i will try my best to help you if you post picture in another question

8 0

3 years ago

Arte-miy333 [17]

Ok then um so ya ok thx for the points though

4 0

3 years ago

olasank [31]

Then, it would be 156 + 156*6.5 /100 = 156+10.14 = $166.14

8 0

3 years ago

tresset_1 [31]

2876.74665 in

After the in you got to put a number 2 above it I don't know how to make the symbol.

7 0

3 years ago