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Advocard [28]
3 years ago
7

Find y, at and tu I need help please help

Mathematics
2 answers:
lesantik [10]3 years ago
8 0

Answer:

there is no picture... but i will try my best to help you if you post picture in another question

eimsori [14]3 years ago
8 0
I can’t see the picture, i wish i could help :(
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Which equation can be used to solve for in the following diagram?
g100num [7]

Answer:

Choice C should be the answer

Step-by-step explanation:

Because all of them adds up to 180 since it is a straight angle.

6 0
3 years ago
NEED HELP NOW!! FOR MATH 10PTS
meriva

Answer:

a)

Step-by-step explanation:

Cost function = revenue function - profit function

   = -0.3x² + 150x - [-0.5x² + 250x - 300]

   = -0.3x² + 150x + 0.5x² - 250x +300

  = -0.3x² + 0.5x² + 150x - 250x + 300   {Combine like terms}

  = 0.2x² - 100x + 300

4 0
3 years ago
Find the median of the data in the pictograph below. Caroline has 2. Samuel has 4. Abby has 4. Jason has 2
atroni [7]

Answer:

3

Step-by-step explanation:

The median is the central number of the data. Align numerically (2, 2, 4, 4) and find the center number. Since there are two, find the average of 2 and 4 to get 3. ([2+4]/2=3)

3 0
3 years ago
Read 2 more answers
Given that −4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f
GalinKa [24]

Answer:

\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in \mathbb{R}.

\\f(x)=(x^2+16)(x^2-2x-15)

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}

And we can write in \mathbb{C}

f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0
3 years ago
Graph the following piecewise function<br> please wait wile i upload my image
Levart [38]

im not sure i cant find a graph but i can find the points for u to graph if u want

3 0
4 years ago
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