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Harman [31]
3 years ago
10

6. A dolphin swims at 2.0 km/hr. How far (in meters) will it travel in 1.50 hr?

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
8 0
C. 3,000m
hope this helps :)
stiv31 [10]3 years ago
7 0

Answer:

Step-by-step explanation:

1200

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2 years ago
1 1/4mi = ft, can someone explain this to me
skelet666 [1.2K]
First off, we'll convert the mixed fraction to "improper" and check about, keeping in mind that, there are 5280 feet in 1mile.

\bf \stackrel{mixed}{1\frac{1}{4}~mi}\implies \cfrac{1\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{5}{4}~mi}\\\\
-------------------------------

\bf \begin{array}{ccll}
feet&miles\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
5280&1\\
f&\frac{5}{4}
\end{array}\implies \cfrac{5280}{f}=\cfrac{1}{\quad \frac{5}{4}\quad }\implies \cfrac{5280}{f}=\cfrac{\frac{1}{1}}{\quad \frac{5}{4}\quad }
\\\\\\
\cfrac{5280}{f}=\cfrac{1}{1}\cdot \cfrac{4}{5}\implies \cfrac{5280}{f}=\cfrac{4}{5}\implies \cfrac{5280\cdot 5}{4}=f\implies 6600=f
4 0
3 years ago
Identify the range of the function shown in the graph.
Schach [20]
Option c would be correct
8 0
4 years ago
ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ДАЮ 23 ОЧКА!!!
posledela

(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 <em>y</em> ², radius <em>y</em>, and thickness ∆<em>y</em>, thus contributing an area of 2<em>π</em> <em>y</em> (3 - 3/4 <em>y</em> ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ <em>y</em> ≤ 2, thus given by the integral

\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 <em>x</em>), thus contributing an area of <em>π</em> (√(4/3 <em>x</em>))² = 4<em>π</em>/3 <em>x</em>. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ <em>x</em> ≤ 3, or by the integral

\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi

Using either method, the volume is 6<em>π</em> ≈ 18,85. I do not know why your textbook gives a solution of 90,43. Perhaps I've misunderstood what it is you're supposed to calculate? On the other hand, textbooks are known to have typographical errors from time to time...

8 0
3 years ago
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