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Vaselesa [24]
3 years ago
10

Louisa savings change - $9 each time she goes bowling. In all, it changed by -99 during the summer. How many times did she go bo

wling during the summer?
Mathematics
2 answers:
Sidana [21]3 years ago
7 0
Well, if you do 99/9 that equals 11, therefor she has gone 11 times.
Alika [10]3 years ago
3 0
The answer is eleven
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because 2x0=0, 2x50=100, 30x0=0, 30×50=1500 add together, than get 1600

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The table below represents a linear function f(x) and the equation represents a function g(x):
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Answer:

<u>Use 2 points from he table to find the slope of f(x):</u>

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<u>The slope is:</u>

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The y - intercept is b = -1 according to point (0, -1).

<h3>Part A</h3>

<u>The lines are:</u>

  • f(x) = 8x - 1
  • g(x) = 3x - 2

The f(x) has greater slope since 8 > 3 and greater y-intercept since -1 > - 2.

<h3>Part B</h3>

See above

8 0
3 years ago
vipins age in 15 years will be 5 less than three times of his age now. what will be his age after 20 years from now?
Shalnov [3]

Answer:

40.

Step-by-step explanation:

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4 0
3 years ago
the equation shows the radius of the algae,f(d), in mm,after d days: f(d)=7(1.06)^d the radius of the algae was approximately 13
Andrei [34K]

Answer:

\begin{gathered} A)\text{ }Domain:\text{ \lparen0,11\rparen} \\ B)\text{ the y-intercept represents that in 0 days the diameter of the algae will be 7 mm.} \\ C)\text{ rate of change= 0.64. This means that on average the algae grows 0.64mm per day.} \end{gathered}

Step-by-step explanation:

If the radius of the algae was approximately 13.29 mm, substitute f(d)=13.29 and solve for d to determine the domain:

\begin{gathered} 13.29=7\left(1.06\right)^d \\ \frac{13.29}{7}=1.06^d \\ d=\frac{\text{ log\lparen13.29/7\rparen}}{\text{ log\lparen1.06\rparen}} \\ d=11 \\ \text{ Then, the domain:} \\ (0,11) \end{gathered}

B. The y-intercept is obtained when d=0, hence;

\begin{gathered} d=0 \\ f(0)=7(1.06)^0 \\ f(0)=7 \end{gathered}

Therefore, the y-intercept represents that in 0 days the diameter of the algae will be 7 mm.

C. Now, to determine the rate of change of a function, use the following equation:

\text{ rate of change=}\frac{change\text{ over y}}{change\text{ over x}}

Then, determine the value of f(4):

\begin{gathered} f(4)=7(1.06)^4 \\ f(4)=8.83 \end{gathered}

Hence, the rate of change on that interval of the function:

\begin{gathered} \text{ rate of change=}\frac{13.29-8.83}{11-4} \\ \text{ rate of change=0.64 } \end{gathered}

This means that on average the algae grows 0.64mm per day.

8 0
1 year ago
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