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3 years ago

Writing an inequality for x that would give this rectangle a perimeter of at least 300 ft.

Mathematics

2 answers:

sdas [7]3 years ago

4 0

This is how I did it, I really hope it helped you with your homework

WINSTONCH [101]3 years ago

3 0

Answer:

142≤ x.

Step-by-step explanation:

Given : rectangle a perimeter of at least 300 ft and Length: 3ft and width formula: x+5ft.

To find : Writing an inequality for x that would give this rectangle a perimeter.

Solution : We have given length = 3 ft.

Width = x + 5 ft .

Perimeter = 300 feet .

Perimeter = 2 ( length + width ) .

Plugging the values and greater than equal to sign for at least.

300 ≤ 2( 3 + x +5).

300≤ 2( 8 +x) .

300≤ 16 + 2x

On subtracting both sides by 16.

300 -16 ≤ 2x .

284 ≤ 2x.

On dividing both sides by 2.

142≤ x.

We can say x is at least 142.

Therefore, 142≤ x.

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3 years ago

Solve for x…..…………………

anzhelika [568]

Answer:

x = 11

Step-by-step explanation:

From the diagram, we find,

(2x - 16) + (x - 8) = 9

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8 0

2 years ago

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brilliants [131]

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Step-by-step explanation:

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3 years ago

Find the area of the composite figure.

Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

According to the Figure Given:

Total Horizontal Distance = 14 in

Length = 6 in

To Find :

The Area of the composite figure

Solution:

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

3 0

2 years ago

Can someone tell me the answer please?

vovikov84 [41]

6.241 I think that's right

4 0

3 years ago