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quester [9]
3 years ago
15

Writing an inequality for x that would give this rectangle a perimeter of at least 300 ft.

Mathematics
2 answers:
sdas [7]3 years ago
4 0
This is how I did it, I really hope it helped you with your homework

WINSTONCH [101]3 years ago
3 0

Answer:

142≤ x.

Step-by-step explanation:

Given : rectangle a perimeter of at least 300 ft and Length: 3ft  and width formula: x+5ft.

To find : Writing an inequality for x that would give this rectangle a perimeter.

Solution : We have given length = 3 ft.

Width = x + 5 ft .

Perimeter =  300 feet .

Perimeter = 2 ( length + width ) .

Plugging the values and greater than equal to sign for at least.

300 ≤ 2( 3 + x +5).

300≤ 2( 8 +x) .

300≤ 16 + 2x

On subtracting both sides by 16.

300 -16 ≤ 2x .

284 ≤ 2x.

On dividing both sides by 2.

142≤ x.

We can say x is at least 142.

Therefore, 142≤ x.

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In a town in Canada, the temperature was 20 °F at sunset. The temperature decreases by 2 every hour. How many hours does it take
Pavel [41]

Answer:

C. 13

Step-by-step explanation:

7 0
3 years ago
Can someone plsss help me :((
nevsk [136]

Answer:

No

Step-by-step explanation:

equation is y=2x+3

The point we have is (15,29)

i.e. x=15 and y=29

if we put x=15 in the equation we should get the value of y=29

y=2(15)+3

=30-3

=27

Here, we didn't get y=29 instead we got y=27

So the point (15,29) doesn't follow that equation

6 0
2 years ago
Allyson has 4.5 pieces of rope to use for a tire swing. If each full piece is 2 2/3 feet long, how much rope does Allyson have i
Scorpion4ik [409]

Answer:

12 feet

Step-by-step explanation:

4.5 pieces of rope = 9/2 pieces in fractions

Also, 2 2/3 can be rewritten as 8/3 in fractions

So, 9/2 *8/3 = 72/6 = 12 feet

Allyson has 12 feet of rope in all.

6 0
3 years ago
NEED HELP ASAP., <br><br> WILL GIVE BRAINLIEST
kow [346]
The answer is 9 1/2
6 0
3 years ago
Read 2 more answers
If sin theta = sqrt(2/2), which could not be the value of theta?
Nataliya [291]

The solution would be like this for this specific problem:

sin(θ°) = √(2)/2 

θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° − sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ 

360°*0 + 45° = 45° 
360°*0 + 135° = 135° 
360°*1 + 45° = 405° 

<span>sin(225°) = -√(2)/2

</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta cannot be 225 degrees.

4 0
3 years ago
Read 2 more answers
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