It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).
So, First we will do the sum of the three given polynomials,
Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)
=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)
=4a+8c
Now, we can perform the subtraction,
∴ Required difference
=(4a+8c)−(2a−3b+4c)
=4a+8c−2a+3b−4c
=2a+3b+4c
The answer to that problem is 4. 4*4*4*4=(4*4)*(4*4)=16*16=256. I hope this helped!
Answer:
sorry i need points :(
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Step-by-step explanation:
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11-
Taking y to the other side;
11-3-6x=
8-6x=
Multiply each side by 2
16-12x=y
y=16-12x
