Answer:
Claim 2
Step-by-step explanation:
The Inscribed Angle Theorem* tells you ...
... ∠RPQ = 1/2·∠ROQ
The multiplication property of equality tells you that multiplying both sides of this equation by 2 does not change the equality relationship.
... 2·∠RPQ = ∠ROQ
The symmetric property of equality says you can rearrange this to ...
... ∠ROQ = 2·∠RPQ . . . . the measure of ∠ROQ is twice the measure of ∠RPQ
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* You can prove the Inscribed Angle Theorem by drawing diameter POX and considering the relationship of angles XOQ and OPQ. The same consideration should be applied to angles XOR and OPR. In each case, you find the former is twice the latter, so the sum of angles XOR and XOQ will be twice the sum of angles OPR and OPQ. That is, angle ROQ is twice angle RPQ.
You can get to the required relationship by considering the sum of angles in a triangle and the sum of linear angles. As a shortcut, you can use the fact that an external angle is the sum of opposite internal angles of a triangle. Of course, triangles OPQ and OPR are both isosceles.
The initial value of the graph is where 
. Thus, in this case, the initial value is 12.
The rate of change of the graph is essentially the slope of the graph. In this case, we can use the slope formula:
and 
are points on the graph
Let's use two points from the chart to find the slope:
In this case, the rate of change of the graph is 9.
Hello,
Why "Multiply the polynomial by distribution" ?
It's s t u p i d, you compliquate the equation.
In order to find the roots of P(a)=(a-3)(a²+2a-6)=0
a²+2a-6
=(a²+2a+1)-7
=(a+1)²-7
=(a-√7)(a+√7)
P(a)=(a-3)(a-√7)(a+√7)
Roots are 3,√7 and -√7
(If i have well understood the question , sorry if not)
They are both a multiple of the number 3
Yes. If we multiply 6/13 by 1 in the form of 5/5, we obtain the fraction 30/65 without ever changing the value of the number itself.
