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Gemiola [76]
3 years ago
12

List down three angles formed when a transversal intersects the two lines​

Mathematics
1 answer:
aleksley [76]3 years ago
8 0

Answer:

The intersections of a transversal with two lines create various types of pairs of angles: consecutive interior angles, consecutive exterior angles, corresponding angles, and alternate angles.

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According to a poll, 80% of California adults (403 out of 506 surveyed) feel that education is one of the top issues facing Cali
fiasKO [112]

f(h(x))= 2x -21

Step-by-step explanation:

f(x)= x^3 - 6

h(x)=\sqrt[3]{2x-15}

WE need to find f(h(x)), use composition of functions

Plug in h(x)

f(h(x))=f(\sqrt[3]{2x-15})

Now we plug in f(x) in f(x)

f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6

cube and cube root will get cancelled

f(h(x))= 2x-15 -6= 2 x-21

6 0
3 years ago
What is the equation of a line that passes through the point(3,-8)and has a slope of 0?
hram777 [196]

Answer: y=-8

Step-by-step explanation:

If the slope is zero that means that the line does not go up (or have any rise) and therefore must be a horizontal line. Since it passes through the point (3,-8), the equation has to be y=-8.

7 0
2 years ago
Ella purchased a game that was on sale for 12% off. The sales tax in her county is 6%. Let y represent the original price of the
egoroff_w [7]

Answer: what was the original price?

Step-by-step explanation:

3 0
3 years ago
) a, p and d are n×n matrices. check the true statements below:
BigorU [14]
A. False. Consider the identity matrix, which is diagonalizable (it's already diagonal) but all its eigenvalues are the same (1).

b. True. Suppose \mathbf P is the matrix of the eigenvectors of \mathbf A, and \mathbf D is the diagonal matrix of the eigenvalues of \mathbf A:


\mathbf P=\begin{bmatrix}\mathbf v_1&\cdots&\mathbf v_n\end{bmatrix}

\mathbf D=\begin{bmatrix}\lambda_1&&\\&\ddots&\\&&\lambda_n\end{bmatrix}

Then

\mathbf{AP}=\begin{bmatrix}\mathbf{Av}_1&\cdots&\mathbf{Av}_n\end{bmatrix}=\begin{bmatrix}\lambda_1\mathbf v_1&\cdots&\lambda_n\mathbf v_n\end{bmatrix}=\mathbf{PD}

In other words, the columns of \mathbf{AP} are \mathbf{Av}_i, which are identically \lambda_i\mathbf v_i, and these are the columns of \mathbf{PD}.

c. False. A counterexample is the matrix

\begin{bmatrix}1&1\\0&1\end{bmatrix}

which is nonsingular, but it has only one eigenvalue.

d. False. Consider the matrix

\begin{bmatrix}0&1\\0&0\end{bmatrix}

with eigenvalue \lambda=0 and eigenvector \begin{bmatrix}k&0\end{bmatrix}^\top, where k\in\mathbb R. But the matrix can't be diagonalized.
7 0
3 years ago
A magazine ad states that 4 out of 7 doctors recommend Flash toothpaste. if 1400 doctors were surveyed, how many doctors recomme
Paladinen [302]

Answer:

The number of doctors recommended flash toothpaste <u>800</u>.

Step-by-step explanation:

Given:

A magazine ad states that 4 out of 7 doctors recommend Flash toothpaste.

Now, to find the numbers of doctors recommended flash toothpaste if 1400 doctors were surveyed.

Let the number of doctors recommended be x.

And the total number of doctors surveyed were 1400.

So, as given 4 out of 7 doctors recommend flash toothpaste.

So, 4 equivalent to 7 = \frac{4}{7}.

And, x equivalent to 1400 =\frac{x}{1400}.

Thus, we set the proportion and solve by cross multiplication method:

\frac{4}{7} =\frac{x}{1400}

<em>By cross multiplying we get:</em>

5600=7x

<em>Dividing both sides by 7 we get:</em>

800=x

x=800.

Therefore, the number of doctors recommended flash toothpaste 800.

3 0
3 years ago
Read 2 more answers
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