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BartSMP [9]
3 years ago
6

This is due today!!! Please help!!! C. What number is 40% of 160

Mathematics
1 answer:
Vika [28.1K]3 years ago
6 0

Answer:

64

Step-by-step explanation:

40% = .4

160*.4 = 64

64 = 40% of 160

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[X + y] + 3w? Helpppppp
lana [24]

Answer:

x+y+3w

Step-by-step explanation:

7 0
3 years ago
Find the length of the missing side. Leave your answer in simplest radical form.
lozanna [386]

Answer:

The other side is 7.48 yards.

Step-by-step explanation:

Given that,

Hypotenuse = 15 yards

One leg = 13 yards

We need to find the length of the other leg. We can use the Pythagoras theorem to find it such that,

H^2=b^2+h^2

Where

h is other leg

Put all the values,

h=\sqrt{H^2-b^2} \\\\h=\sqrt{(15)^2-(13)^2} \\\\h=7.48\ yd

So, the other side is 7.48 yards.

6 0
3 years ago
Which is the equation of a circle with its center at (-4,2) and a radius of 4?
Snowcat [4.5K]

Answer:

(x +4)^2 + (y-2)^2 = 16

Step-by-step explanation:

We can write the equation for a circle with the formula

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

We know the center is at (-4,2) and the radius is 4

(x- -4)^2 + (y-2)^2 = 4^2

(x +4)^2 + (y-2)^2 = 16

4 0
3 years ago
An education researcher claims that 58​% of college students work​ year-round. In a random sample of 400 college​ students, 232
Hatshy [7]

Answer:

The proportion of college students who work​ year-round is 58%.

Step-by-step explanation:

The claim made by the education researcher is that 58​% of college students work​ year-round.

A random sample of 400 college​ students, 232 say they work​ year-round.

To test the researcher's claim use a one-proportion <em>z</em>-test.

The hypothesis can be defined as follows:

<em>H</em>₀: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> = 0.58.

<em>Hₐ</em>: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> ≠ 0.58. C

Compute the sample proportion as follows:

 \hat p=\frac{232}{400}=0.58

Compute the test statistic value as follows:

 z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.58-0.58}{\sqrt{\frac{0.58(1-0.58)}{400}}}=0

The test statistic value is 0.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

 p-value=2\times P(z

*Use a z-table for the probability.

The p-value of the test is 1.

The p-value of the test is very large when compared to the significance level.

The null hypothesis will not be rejected.

Thus, it can be concluded that the proportion of college students who work​ year-round is 58%.

6 0
4 years ago
Please help! Thanks in advance.
alukav5142 [94]
In this problem, we need to plug in the given x values for f(x)=0 and find a and b.

When we plug in 1, we get: 2 \times {1}^{4} - 5 \times {1}^{3} - 14 \times {1}^{2} + a \times 1 + b = 0

Simplify:
2 - 5 - 14 + a + b = 0
- 17 + a + b = 0
a + b = 17

We got our first statement about the values of the variables. If we find one more we can find those 2 variables.

We have another given root: 4.

Plug it in:
2 \times {4}^{4} - 5 \times {4}^{3} - 14 \times {4}^{2} + a \times 4 + b = 0
512 - 320 - 224 + 4a + b = 0
- 32 + 4a + b = 0
4a + b = 32

Now we have our second one. We can combine them:
a + b = 17 \\ 4a + b = 32

I use elimination method which is easier here.

Multiply the top equation by -1: - a - b = - 17 \\ 4a + b = 32

Add them up:
3a = 15

Simplify:
a = 5

Now we have a, we can plug in one of those equations to find b:
5 + b = 17
b = 17 - 5
b = 12

So, the answers are a=5 and b=12 .
6 0
3 years ago
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