2 years ago

Someone pls help me with this question

Mathematics

1 answer:

serg [7]2 years ago

5 0

Where is the questoin pls tell me

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5 + 3 . 3x-2 , let x=2

LiRa [457]

Answer:

Step-by-step explanation:

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2 years ago

Solve for X<br><br> Thank youuu

maksim [4K]

Answer:

x= -4

Step-by-step explanation:

∠LMP + ∠PMN= 180° (adj. ∠s on a str. line)

-16x +13 -20x +23= 180

bring x term to 1 side, constant to the other:

-36x= 180 -13 -23

Simplify:

-36x= 144

x= 144 ÷ (-36)

x= -4

*The sum of the angles on a straight line is 180°

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2 years ago

What is 12+ 12-4 %2<br> Hhhhhhhhhhhhhhhhhhhhhhhhhhh

prohojiy [21]

Can you show me a picture of the problem?

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2 years ago

If you had to add two fractions with denominators of 4 and 5. What might the denominator of the sum be? Show more than one possi

Fiesta28 [93]

Answer:

Step-by-step explanation:

4 0

2 years ago

Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9

natulia [17]

Parameterize $C$ by

$\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle$

where $0\le t\le\pi$ . Then the line integral is

$\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt$
$=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt$
$=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt$

Take $u=\cos t$ , then

$=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du$
$=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du$
$=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du$
$=54$

6 0

3 years ago