Can yall plz help I´ll give brainliest

The distribution of weights of potato chip bags filled off a production line is unknown. However, the mean is m=13.35 OZs and th

Nikitich [7]

Answer:

a) $\mu_{\bar X} =13.35$

e.none of the above

b) $\sigma_{\bar X}= \frac{0.12}{\sqrt{36}}= 0.02$

a.0.0200

c) $z = \frac{13.32-13.35}{\frac{0.12}{\sqrt{36}}}= -1.5$

$P(\bar X< 13.32)= P(z$

a.0.0668

d) $z = \frac{13.30-13.35}{\frac{0.12}{\sqrt{36}}}= -2.5$

$z = \frac{13.36-13.35}{\frac{0.12}{\sqrt{36}}}= 0.5$

$P(13.30$

c.0.6853

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(13.35,0.12)$

Where $\mu=13.35$ and $\sigma=0.12$

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Part a

$\mu_{\bar X} =13.35$

Part b

$\sigma_{\bar X}= \frac{0.12}{\sqrt{36}}= 0.02$

Part c

We want this probability:

$P(\bar X< 13.32)$

For this case we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using this formula we got:

$z = \frac{13.32-13.35}{\frac{0.12}{\sqrt{36}}}= -1.5$

$P(\bar X< 13.32)= P(z$

Part d

We want this probability:

$P(13.30$

For this case we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using this formula we got:

$z = \frac{13.30-13.35}{\frac{0.12}{\sqrt{36}}}= -2.5$

$z = \frac{13.36-13.35}{\frac{0.12}{\sqrt{36}}}= 0.5$

$P(13.30$

8 0

3 years ago

Sarah sells beaded necklaces she makes a profit of $4 on every necklace she sells which table represents the profit Sarah makes

Bogdan [553]

Answer:

The correct table is A.

Correct statement and question:

Sarah sells beaded necklaces she makes a profit of $4 on every necklace she sells which table represents the profit Sarah makes.

A.

Necklaces Sold Profit $

4 16

6 24

8 32

10 40

B.

Necklaces Sold Profit $

4 8

6 10

8 12

10 14

C.

Necklaces Sold Profit $

4 4

6 8

8 12

10 16

D.

Necklaces Sold Profit $

4 16

6 20

8 24

10 28

Source:

North Carolina Practice Test

Step-by-step explanation:

If Sarah makes a profit of $ 4 on every necklace she sells, then:

4 necklaces = 4 * 4 = $ 16

6 necklaces = 6 * 4 = $ 24

8 necklaces = 8 * 4 = $ 32

10 necklaces = 10 * 4 = $ 40

The correct table is A.

6 0

3 years ago

A bond is initially bought for $250. It doubles in value every decade.Write an equation relating v, the value of the bond, to d,

Juliette [100K]

Answer:

V=250(2d)

Step-by-step explanation:

5 0

4 years ago

ASAPPPPPP NO LINK OR FILE GET RIGHT, BRAINEST!

Kaylis [27]

Answer:

834.24.

Step-by-step explanation:

cuando el por qué y la lata si el cuando y ver la respuesta del número es ochocientos treinta y cuatro punto veinticuatro.

5 0

3 years ago

Find the number of outcomes in the complement of the given event.

stealth61 [152]

Answer:

96

Step-by-step explanation:

Out of 270 apartments in a complex, 174 are subleased.

Given that :

Total number of apartments in complex = 270

Number subleased = 174

The complement of event A = not A

Therefore, The complement in this scenario is NOT SUBLEASED ;

Hence, the Number of apartments in complex not subleased is :

Total apartment in complex - number subleased

270 - 174 = 96

5 0

3 years ago