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2 years ago

What is the best way to protect computer equipment from damage caused by electrical spikes?

2 answers:

4 0

Plug equipment into a surge protector because that will take most of the spike of electricity. The plugging everything via USB will be okay if it is connected to a surge protector. Turning off the equipment when not in use will only make the battery live longer if it gets spiked while it is off it will still be messed up. Recharging equipment is only good for when you don't have any power and need to use this certain device. So now that i have gone over all of the options it should be clear that plugging your electronics into a surge protector is best out of all of the options.

suter [353]2 years ago

3 0

Answer:

the short answer would be D plug equipment into surge protector

Explanation:

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The way a particular application views the data from the database that the application uses is a.

masha68 [24]

The way a particular application views the data from the database that the application uses is a sub-schema.

<h3>What is Database?</h3>

A Database may be defined as a process of collecting data and information that is principally assembled for quick search and recoupment by a computer.

The sub-schema is the reasoning elucidation of that section of the database which is applicable and accessible to a specific application. This type of database is common to two or more applications.

Therefore, the sub-schema is the way through which a particular application views the data from the database that the application uses.

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1 year ago

Question is attached as image, please help :>

harkovskaia [24]

Answer:

Proved

Explanation:

Given

$X = (a.\bar b)+(\bar a.b)$

$(a + b)\ .$ $\frac{}{a.b}$

Required

Find out why they represent the same

To do this, we simplify either $(a + b)\ .$ $\frac{}{a.b}$ or $X = (a.\bar b)+(\bar a.b)$

In this question, I will simplify $(a + b)\ .$ $\frac{}{a.b}$

Apply de morgan's law

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $(a + b) . (\bar a + \bar b)$

Apply distribution property

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $a.\bar a + a.\bar b + \bar a . b + b . \bar b$

To simplify, we apply the following rules:

$a.\bar a = 0$ --- Inverse law

$b.\bar b = 0$ --- Inverse law

So, the expression becomes

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $0 + a.\bar b + \bar a.b + 0$

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $a.\bar b + \bar a.b$

Rewrite as:

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $(a.\bar b)+(\bar a.b)$

From the given parameters:

$X = (a.\bar b)+(\bar a.b)$

This implies that:

$(a + b)\ .$ $\frac{}{a.b}$ when simplified is X or $(a.\bar b)+(\bar a.b)$

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2 years ago

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hoa [83]

Answer:

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3 years ago

Steps for turning off 2 step verification on iPhones

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If it’s for the App Store, follow this
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