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atroni [7]
3 years ago
7

Please help asap!!!!

Mathematics
2 answers:
nordsb [41]3 years ago
6 0
144.Tip: 12•12 I think
oksian1 [2.3K]3 years ago
5 0

Answer:

144

Step-by-step explanation:

Length of 1 side is 12 so area is 12*12

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2,5-[0,2+(-3,7+5)-1,4]
ValentinkaMS [17]

2.5 - (0.2 + (3.7 + 5) - 1.4) \\  = 2.5 - (0.2 + 4.2 - 1.4) \\  = 2.5 - (4.4 - 1.4) \\  = 2.5 - 3 \\  =  - 0.5
7 0
3 years ago
Read 2 more answers
The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it
brilliants [131]

Answer:

(a) 11.25 and 1.68  

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 15

             r = number of success

             p = probability of success which in our question is % of cases in

                  which customer problems are resolved on the same day, i.e.;75%

So, here X ~ Binom(n=15,p=0.75)

(a) Expected number of problems to be resolved today = E(X)

            E(X) = \mu = n * p = 15 * 0.75 = 11.25

    Standard deviation = \sigma = \sqrt{n*p*(1-p)} = \sqrt{15*0.75*(1-0.75)} = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

     P(X = 10) = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}

                    = 3003*0.75^{10} *0.25^{5} = 0.1651

(c) Probability that 10 or 11 of the problems can be resolved today is given by = P(X = 10) + P(X = 11)

    = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}

    = 3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4} = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

    given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)  

= \binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}

= 1365*0.75^{11} *0.25^{4} + 455*0.75^{12} *0.25^{3}+105*0.75^{13} *0.25^{2} + 15*0.75^{14} *0.25^{1}+1*0.75^{15} *0.25^{0}

= 0.6865

3 0
3 years ago
What is 4/17 as a decimal
Stells [14]
<span><span>Step 1: Find a number you can multiply by the bottom of the fraction to make it 10, or 100, or 1000, or any 1 followed by 0s.

</span><span>Step 2: Multiply both top and bottom by that number.

</span><span>Step 3.Then write down just the top number, putting the decimal point in the correct spot (one space from the right hand side for every zero in the bottom number)</span></span><span> 

Hope i helped :[)</span>
6 0
3 years ago
I'm really not sure how to go about solving this algebraic equation, please help! .513 = (2x)^2 / (.05-x)
LiRa [457]
Let's set it up like this:
0.513=\frac{\left(2x\right)^2}{\left(0.05-x\right)}
Multiply both sides by 0.05-x
0.513\left(0.05-x\right)=\frac{\left(2x\right)^2}{0.05-x}\left(0.05-x\right)
0.513\left(0.05-x\right)=4x^2
We are then going to use the distributive property. Since we also know that the opposite of an number that is squared is the square root, we can also apply that. We would be left with something like this:
x=-\frac{0.513+\sqrt{0.673569}}{8},\:x=\frac{\sqrt{0.673569}-0.513}{8}
The variable x can be both positive or negative.
We have found successfully our answer.

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish<span />
4 0
3 years ago
In this line of ,the ratio of red circles to blue circles is 1:3 , How many more red circles would need to be added to make the
avanturin [10]

8 more red circles because if you have 9 red circles and 3 blue ones the ratio would be 9:3 and if you simplify that down to 3:1 that’s the answer. So you would need to add 8 more red circles

5 0
3 years ago
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