Answer
Area of the figure = 105.12 ft²
Explanation
The figure shown is a combination of a rectangle with length 10 ft. and width 8 ft., with a semicircle that has diameter 8 ft., which translates to a radius of 4 ft.
The area of the figure = (Area of the rectangle) + (Area of the semicircle)
Area of rectangle = L × W
L = Length = 10 ft.
W = Width = 8 ft.
Area of the rectangle = 10 × 8 = 80 ft²
Area of semicircle = Half of the area of a circle = ½ × πR²
π = pi = 3.14 (According to the question)
R = Radius of the semicircle = 4 ft.
Area of semicircle = ½ × 3.14 × 4² = 25.12 ft²
Area of the figure = 80 + 25.12 = 105.12 ft²
Hope this Helps!!!
I believe it is asking for the same number basically written 3 different ways, so it could be 1 1/2, 6/4 and 1.5 because those are all the same number
We have a three unknown, 4 equation homogeneous system. These always have at least (0,0,0) as a solution. Let's write the equations, one column at a time.
1a + 0b + 0c = 0
-1a + 1b +0c = 0
0a - 1b + c = 0
0a + 0b + -1 c = 0
We could do row reduction but these are easy enough not to bother.
Equation 1 says
a = 0
Equation 4 says
c = 0
Substituting in the two remaining,
-1(0) + 1b + 0c = 0
b = 0
0(0) - 1b + 0 = 0
b = 0
The only 3-tuple satisfying the vector equation is (a,b,c)=(0,0,0)
Add up all.
Yards = 29 + 55 + 13 = 97
Feet = 2 + 1 + 1 = 4
Inches = 11 + 10 + 3 = 24
In conclusion your final anwser is
97 yd. 4 ft. 24 in.
Hope this helps!
Have a great day.
