All categories

2 years ago

How to find MP when discount percent and SP are given

Mathematics

1 answer:

nadezda [96]2 years ago

7 0

Given:

Consider the discount percent and SP are given.

To find:

The MP.

Solution:

Let x% be the discount percent Then

$SP=MP-x\%\text{ of }MP$

$SP=MP-\dfrac{x}{100}MP$

$SP=\left(1-\dfrac{x}{100}\right)MP$

$SP=\left(\dfrac{100-x}{100}\right)MP$

Multiply both sides by 100.

$100SP=(100-x)MP$

Divide both sides by $(100-x)$ .

$\dfrac{100}{100-x}SP=MP$

Therefore, the formula for MP is $MP=\dfrac{100}{100-x}SP$ , where x is the discount percentage.

You might be interested in

What are some good notes I can use to study for my algebra exam tomorrow?

zlopas [31]

Answer:

all you need to do is look over your notes continue to partice as much as you can

Step-by-step explanation:

you got this

4 0

2 years ago

Read 2 more answers

According to an article, 47% of adults have experienced a breakup at least once during the last 10 years. Of 9 randomly select

In-s [12.5K]

Answer:

a) $P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

b) $P(X=0)=(9C0)(0.47)^0 (1-0.47)^{9-0}=0.0033$

And replacing we got:

$P(X \geq 1)= 1-P(X$

c) $P(X=4)=(9C4)(0.47)^4 (1-0.47)^{9-4}=0.257$

$P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

$P(X=6)=(9C6)(0.47)^6 (1-0.47)^{9-6}=0.135$

And adding we got:

$P(4 \leq X \leq 6)= 0.257+0.228+0.135=0.620$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=9, p=0.47)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Assuming the following questions:

a. exactly five

For this case we can use the probability mass function and we got:

$P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

b. at least one

For this case we want this probability:

$P(X \geq 1)$

And we can use the complement rule and we got:

$P(X \geq 1)= 1-P(X$

$P(X=0)=(9C0)(0.47)^0 (1-0.47)^{9-0}=0.0033$

And replacing we got:

$P(X \geq 1)= 1-P(X$

c. between four and six, inclusive.

For this case we want this probability:

$P(4 \leq X \leq 6)$

$P(X=4)=(9C4)(0.47)^4 (1-0.47)^{9-4}=0.257$

$P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

$P(X=6)=(9C6)(0.47)^6 (1-0.47)^{9-6}=0.135$

And adding we got:

$P(4 \leq X \leq 6)= 0.257+0.228+0.135=0.620$

6 0

3 years ago

PLEASE HELP ASAP !!

wariber [46]

Answer:

First figure: $954cm^3$

Second figure: $1,508yd^3$

Third figure:

Height= q
Side length = r

Fourth figure:  $726cm^3$

Explanation:

A. First figure:

1. Formula:

$\text{Volume of a cylinder}=\pi \times radius^2\times length$

2. Data:

radius = 9cm / 2 = 4.5cm

length = 15 cm

3. Substitute in the formula and compute:

$Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3$

B. Second figure

1. Formula:

$\text{Volume of a leaned cylinder}=\pi \times radius^2\times height$

2. Data:

radius = 12yd

height = 40 yd

3. Substitute and compute:

$Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3$

C) Third figure

a) The height is the segment that goes vertically upward from the center of the base to the apex of the pyramid, i.e. q .

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e. r .

When the base of the pyramid is a square the four edges of the base have the same side length.

D) Fourth figure

1. Formula

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

$Volume=(1/3)B\times H$

2. Data:

height: H = 18cm

side length of the base: 11 cm

3. Calculations

a) Calculate the area of the base.

The base is a square of side length equal to 11 cm:

$\text{Area of the base}=B=(11cm)^2=121cm^2$

b) Volume of the pyramid:

$Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3$

4 0

3 years ago

Read 2 more answers

Y = x + 2 2x - y = -4

mrs_skeptik [129]

1.) X=-2

2.) 2x-y+4=0

Hope this helps! :))

3 0

2 years ago

Which expression is equivalent to 1/2 (2n+6)?

Fynjy0 [20]

Multiply the bracket by 1/2

1/2(2n +6)

cross out 2 and 2n and divide by 2.

cross out 6 and 2 and divide by 2

n+3

Answer is n+3

7 0

2 years ago

Read 2 more answers

How to find MP when discount percent and SP are given​

How to find MP when discount percent and SP are given