Answer:
all you need to do is look over your notes continue to partice as much as you can
Step-by-step explanation:
you got this
Answer:
a) 
b) 
And replacing we got:

c) 


And adding we got:

Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Solution to the problem
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Assuming the following questions:
a. exactly five
For this case we can use the probability mass function and we got:

b. at least one
For this case we want this probability:

And we can use the complement rule and we got:


And replacing we got:

c. between four and six, inclusive.
For this case we want this probability:




And adding we got:

Answer:
<u>First figure:</u> 
<u>Second figure:</u> 
<u>Third figure:</u>
- Height= q
- Side length = r
<u>Fourth figure: </u> 
Explanation:
<u></u>
<u>A. First figure:</u>
<u>1. Formula:</u>

<u>2. Data:</u>
<u>3. Substitute in the formula and compute:</u>

<u>B. Second figure</u>
<u>1. Formula: </u>

<u>2. Data:</u>
<u>3. Substitute and compute:</u>

<u></u>
<u>C) Third figure</u>
a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u> </u><u>q </u>.
The apex is the point where the three leaned edges intersect each other.
b) The side length is the measure of the edge of the base, i.e.<u> r </u><u> </u>.
When the base of the pyramid is a square the four edges of the base have the same side length.
<u>D) Fourth figure</u>
<u>1. Formula</u>
The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

<u>2. Data: </u>
- side length of the base: 11 cm
<u>3. Calculations</u>
a) <u>Calculate the area of the base</u>.
The base is a square of side length equal to 11 cm:

b) <u>Volume of the pyramid</u>:

1.) X=-2
2.) 2x-y+4=0
Hope this helps! :))
Multiply the bracket by 1/2
1/2(2n +6)
cross out 2 and 2n and divide by 2.
cross out 6 and 2 and divide by 2
n+3
Answer is n+3