Answer:
Step-by-step explanation:
y = 3x
y = 3x - 3
y = 3x + 3
all of these equations have a slope of 3 and different y intercepts, therefore, all of these lines are parallel and never cross each others path.
The sum of the 3 consecutive positive integers is 110. What are the numbers? What are the equations used to solve this problem?
Since we require the sum of the squares to equal 110 ⇒ X² + (X+1)² + (X+2)² = 110 Expanding the left-hand side: X² + X² + 2·X + 1 + X² +4·X + 4 = 110 3·X² + 6·X + 5 = 110 3·X² + 6·X - 105 = 0 Solve utilizing the quadratic formula and you get roots: X = 5, X = -7 Your quandary doesn't verbalize that we have to restrict the solution to positive integers only and since we are summing the squares we have 2 solutions that work: 5, 6, 7 and -7, -6, -5
3/4 divided by 3/8= 2
Hope this helps!! <3
X = 11 x cos(22) = 10.199 = 10.2