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3 years ago

1 1/12 will be greater than, less than, or equal to 1 5/8?

Mathematics

1 answer:

creativ13 [48]3 years ago

4 0

Answer:

1 1/12 is less than 1 5/8

Step-by-step explanation:

Turn 1 1/12 into An improper fraction. Multiply the denominator (12) by the whole number (1). =12

Add 1 to 12= 13

13/12= 1.083 decimal

1 5/8 into an improper fraction

8*1=8

8+5= 13/8

13/8= 1.625 decimal.

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3 years ago

In the picture I need the answers to the questions.

IrinaK [193]

Answer:

a) $\mathbf{ f(g(x))=x+2\sqrt{x} +1}$

b) $\mathbf{f(g(9))=16}$

Step-by-step explanation:

We are given:

$f(x)=(x-2)^2\\g(x)=\sqrt{x} +3$

We need to find $a) f(g(x))\\b) f(g(9))$

a) First finding: $f(g(x))$

It can be found by putting the value of g(x) into f(x)

We are given:

$f(x)=(x-2)^2\\Put\:x=g(x)\:i.e. \: x= \sqrt{x} +3\\f(g(x))=(\sqrt{x} +3-2)^2\\Now\: solving:\\f(g(x))=(\sqrt{x} +1)^2\\Using\:formula\:\mathbf{(a+b)^2=a^2+2ab+b^2}\\f(g(x))=(\sqrt{x})^2+2(\sqrt{x} )(1)+(1)^2\\ f(g(x))=x+2\sqrt{x} +1$

SO, we get: $\mathbf{ f(g(x))=x+2\sqrt{x} +1}$

b) Now finding: $f(g(9))$

It can be found by putting x=9 in f(g(x))

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$f(g(x))=x+2\sqrt{x} +1\\Put\:x=9\\f(g(9))=9+2\sqrt{9}+1\\We\:know\: \sqrt{9}=3\\ f(g(9))=9+2(3)+1\\f(g(9))=9+6+1\\f(g(9))=16$

So, we get: $\mathbf{f(g(9))=16}$

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3 years ago

The stack on the left is made up of 15 pennies, and the stack on the right is also made up of 15 pennies. If the volume of the s

emmainna [20.7K]

Answer:

$375\text{ mm}^3$ .

Step-by-step explanation:

We have been given that the stack on the left is made up of 15 pennies, and the stack on the right is also made up of 15 pennies. The volume of the stack of pennies on the left is $375\text{ mm}^3$ . We are asked to find the volume of stack of pennies on the right in cubic millimeters.

Since the pennies in both stacks are of same size, same type, and same in quantity, so the volume of both stacks would be same.

Since the volume of the stack on left is $375\text{ mm}^3$ , therefore, the volume of the stack on right would be $375\text{ mm}^3$ .

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3 years ago

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