In square ABCD, point M is the midpoint of side AB and point N is the midpoint of side BC. What is the ratio of the area of tria
ngle AMN to the area of square ABCD? Express your answer as a common fraction
2 answers:
Answer:
The ratio of the area of triangle AMN to the area of square ABCD is 1:8.
Step-by-step explanation:
Check attachment for solution
Answer:
Ratio of triangle AMN to square ABCD = 1/8
Step-by-step explanation:
area AMN = Area ABN - Area MNB
Where AB = BC = x
Area AMN = [ ½ *( x * ½x )] - [ ½( ½x * ½x)] = x²/8
Area of ABCD = x* x = x²
So therefore:
The ratio of area of triangle AMN to area of square ABCD would be
= (x²/8) / x²
=1/8
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