Question

In square ABCD, point M is the midpoint of side AB and point N is the midpoint of side BC. What is the ratio of the area of triangle AMN to the area of square ABCD? Express your answer as a common fraction

Answer 1

Answer:

The ratio of the area of triangle AMN to the area of square ABCD is 1:8.

Step-by-step explanation:

Check attachment for solution

Answer 2

Answer:

Ratio of triangle AMN to square ABCD = 1/8

Step-by-step explanation:

area AMN = Area ABN - Area MNB

Where AB = BC = x

Area AMN = [ ½ *( x * ½x )] - [ ½( ½x * ½x)] = x²/8

Area of ABCD = x* x = x²

So therefore:

The ratio of area of triangle AMN to area of square ABCD would be

= (x²/8) / x²

=1/8