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Andre45 [30]
3 years ago
6

Activity Convert these mililitres to litres. a. 1436 ml​

Mathematics
2 answers:
DanielleElmas [232]3 years ago
7 0

<em>1436 ml</em>

<em>=</em><em> </em><em>1</em><em>.</em><em>4</em><em>3</em><em>6</em><em> </em><em>l</em>

<em>(</em><em> </em><em>divide</em><em> </em><em>by</em><em> </em><em>1</em><em>0</em><em>0</em><em>0</em><em>)</em>

frosja888 [35]3 years ago
4 0

Answer:

1,436L ,......................

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A bank is reviewing its risk management policies with regards to mortgages. To minimize the risk of lending, the bank wants to c
Mariana [72]

Answer:

1. $ \mu = \$306,500 $

2. \sigma = \$24,500

3. n = 150

4. $ \mu_{x}= \mu = \$306,500 $

5. \sigma_x = \$ 2,000 \\\\

Step-by-step explanation:

The average mortgage owed by Americans is $306,500, with a standard deviation of $24,500.

From the above information, we know that,  

The population mean is

$ \mu = \$306,500 $

The population standard deviation is

\sigma = \$24,500

Suppose a random sample of 150 Americans is selected

n = 150

Since the sample size is quite large then according to the central limit theorem, the sample mean is approximately normally distributed.

The sample mean would be the same as the population mean  that is

$ \mu_{x}= \mu = \$306,500 $

The sample standard deviation is given by

\sigma_x = \frac{\sigma}{\sqrt{n} }

Where \sigma is the population standard deviation and n is the sample size.

\sigma_x = \frac{24,500}{\sqrt{150} }  \\\\\sigma_x = \$ 2,000 \\\\

Therefore, the required parameters are:

1. $ \mu = \$306,500 $

2. \sigma = \$24,500

3. n = 150

4. $ \mu_{x}= \mu = \$306,500 $

5. \sigma_x = \$ 2,000 \\\\

5 0
3 years ago
A movie rental kiosk charges a $25 membership fee and $3 per movie. An online movie service charges a $20 membership fee and $4
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4 years ago
Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt
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If you're just integrating a vector-valued function, you just integrate each component:

\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt

=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k

The first integral is trivial since (\tan t)'=\sec^2t.

The second can be done by substituting u=t^2-1:

u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C

The third can be found by integrating by parts:

u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t

\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8

\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C

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4 years ago
(-x2y3)*(12xy3)<br>(-2xy2)3​
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Assuming the numbers are exponents expect the coefficient of 2, top expression, -12x^3y^6, multiply bottom
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Which equation represents a line that has a slope of -1/2 and passes through point (4, –5)?
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You can rewrite the equation “y=mx+b” and fill in what you know. So your equation would look like y=-1/2x+b when filling in what you know. Now you can take the (x,y) coordinates that you were given and plug them into the equation and solve for b. So now it would be -5=-1/2(4)+b
8 0
3 years ago
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