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Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

4 years ago

Lia has a dog and a cat. Together, the pets weigh 24 pounds. The dog weighs 2 times as much as the cat.

telo118 [61]

Answer:

The dog weighs 16 pounds, while the cat weighs 8 pounds

Step-by-step explanation:

Let's call the weight of the dog d, and the weight of the cat c.

d+c=24

d=2c

Substitute the second equation into the first:

(2c)+c=24

3c=24

c=8

d=24-8=16

Hope this helps!

3 0

3 years ago

Mr. Levy has a budget of $18,000. Uniforms for the marching band cost $315 each, and he needs 62 uniforms. He says, "Since 60x$3

svetoff [14.1K]

Answer:

No. See explanation below.

Step-by-step explanation:

No.

Since 60 × $300 = $18,000, he would be exactly at budget if he needed 60 uniforms and if each uniform cost $300, but he needs more than 60 uniforms, and each uniform costs more than $315, so the total cost is definitely more than $18,000.

7 0

3 years ago

Read 2 more answers

Two coins have a radii of 3 cm and 1 cm the smaller coin rolls along the circumference of the fixed larger coin until the smalle

dezoksy [38]

I think you have to do 3cm/1cm

I think the small coin makes 3 revolution

6 0

4 years ago

Kendall received dollars for his birthday. Joshua received dollars for his birthday. Which of the following is true?

12345 [234]

<span>Kendall's birthday money = Joshua's birthday money</span>

5 0

3 years ago