Answer:
The claim that the scores of UT students are less than the US average is wrong
Step-by-step explanation:
Given : Sample size = 64
Standard deviation = 112
Mean = 505
Average score = 477
To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.
Solution:
Sample size = 64
n > 30
So we will use z test
Formula : 
Refer the z table for p value
p value = 0.9772
α=0.05
p value > α
So, we accept the null hypothesis
Hence The claim that the scores of UT students are less than the US average is wrong
Hi.
Your answer is going to be
C.) 33
Hope this helps! :)
Answer:
1/4
Step-by-step explanation:
the numerator is 12 because there are 12 possible outcomes. The numerator is 3 because there are 3 numbers in this set that are greater than 9. You get 3/12 which then simplifies to 1/4
If you were at 54 on the number line you would have to cross zero and go an extra 13 steps to get to -13.
So we want the difference between 54 and -13 or 54- -13 which becomes 54+13 which is 67 - that is the range
A+c=100
3a+2c=275, from the first c=100-a making the 2nd equation become:
3a+2(100-a)=275 perform indicated multiplication on left side
3a+200-2a=275 combine like terms on left side
a+200=275, subtract 200 from both sides
a=75, and since c=100-a
c=100=75=25
So the answer is D. 25 children and 75 adults
Equation 1: a+c=100
Equation 2: 3a+2c=275
