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3 years ago

How many even 2-digit positive integers can be written using the numbers 2, 4, 5, and 8?

Mathematics

1 answer:

BartSMP [9]3 years ago

7 0

Answer:

Step-by-step explanation:

To have an even integer the number's endian has to be an even number. Consider the 2-digit positive number like _ _ and place the number of possible options out of four total options in each blank space. We have 3 even options, so we can fill the endian blank like this _ 3

Since the first digit can be any number, therefor, we have 4 options for the first blank space 4 3. Just multiply the two numbers and you have the answer.

22, 24, 28, 42, 44, 48, 52, 54, 58, 82, 84, 88

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nika2105 [10]

Answer: 9.38

Step-by-step explanation:

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3 years ago

A shipping box is shaped like a rectangular prism. The box is 1 1/5 feet wide, 3 feet long, and 4 1/2 feet tall. What is the vol

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2 years ago

What is the equation of the circle with center (5,-4) and radius 4

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3 years ago

9. What value of m makes this equation true? 1/2 (8m - 18) = 31

OverLord2011 [107]

Answer:

m = 10

Step-by-step explanation:

The value of m that would make this equation true is 10. To figure this out you must work the equation to combine like terms. To start, remember PEMDAS. You would begin with 1/2 (8m - 18) and multiply both 8m and 18 by 1/2. Because half of 8 is 4 and half of 18 is 9, your new equation would be 4m - 9 = 31. From here you would add nine to both sides to finish combining like terms. The equation from this point should be 4m = 40. To find the value of m, you then have to divide both sides by 4, leading to the equation/solution of m = 10.

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2 years ago

A scale drawing of a field is shown below. The drawing uses a scale of 1 in. = 14 ft. What is the area of the actual field?

svp [43]

Answer:

D. 4,704 ft²

Step-by-step explanation:

Giving a scale of 1 in. = 14 ft, to find the actual area of the field represented by the triangular drawing above, convert the length of the base and height to the actual lengths of the field using the scale.

Height of drawing = 8 in.

Actual height = 8*14 = 112 ft

Base of drawing = 6 in.

Actual base = 6*14 = 84 ft

Area of the field = area of ∆

Area = ½*base*height

Area = ½*84*112

Area = 4,704 ft²

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2 years ago