<span>Helena is correct in saying that the point-slope form
will generate the equation. The point-slope form is written as:</span>
<span>
</span>
y-y₁ = m(x-x₁), where,
m = (y₂-y₁)/(x₂-x₁) is the slope of the line
(x₁,y₁) and (x₂,y₂) are the coordinates of the two points
On the other hand, the slope-intercept form is written as:
y = mx + b, where,
m is the slope of the line
b is the y-intercept
In this case, since only two points were given, the y-intercept of the line is not readily known. Thus, it is only through the point-slope form that the equation of the line can be determined. This is because it only requires the substitution of the x and y-coordinates of the points in the equation.
Step-by-step explanation:
In the attached images we can see the rigid transformation of the function 
1. The basic graph
2. The reflected graph 
3. The displaced graph 
Reflection: In the expression , the sign - before the parenthesis indicates that the function is reflected in the x axis, for this case the function is even, this means that -f(x) = f(-x)
, then the reflection on the x axis is equal to the reflection on the y axis.
Displacement: We observe the term (x-4) of the function and analyze the value -4, where, the sign - indicates displacement to the right and the value 4 indicates the amount that the graph shifted
.
