Question 9 (1 point)
Solve for X
K
50°
110°
P
R
w
30x
1 answer:
Answer:
x = 3
Step-by-step explanation:
Recall: Opposite angles in an inscribed quadrilateral are supplementary.
Thus,
m<R = 180 - m<P
m<R = 180 - 110
m<R = 70°
Recall: measure of inscribed angle = half of the intercepted arc
Thus:
m<R = ½(arc KPQ)
70 = ½(50 + 30x)
Multiply both sides by 2
2*70 = 50 + 30x
140 = 50 + 30x
140 - 50 = 50 + 30x - 50
90 = 30x
90/30 = 30x/30
3 = x
x = 3
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