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vichka [17]
2 years ago
6

What is the difference between adding whole numbers and adding decimals?

Mathematics
1 answer:
noname [10]2 years ago
4 0

Answer:

The only difference is that we line up the numbers according to the decimal point. For addition, it doesn't matter which number goes on the bottom.

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Joseph and Tyler went to the hobby store. They each bought a race car for $15.99. Joseph bought a blue race car for $2.99 and Ty
Svetach [21]
$15.99x2 +2.99+3.99= subtotal

subtotal x .089= Tax due

tax due + subtotal = total spent
38.96*.089= 3.46

3.46 +38.96= 42.42744

so altogether with tax, Joseph and Tyler spent $42.43 at the hobby store
8 0
3 years ago
5
Assoli18 [71]

Answer:

2.9

Step-by-step explanation:

x+3.2=6.1

x=6.1-3.2

x=2.9

6 0
3 years ago
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Can someone help me on this questionnnn no fake answers please!
Rufina [12.5K]

Answer:

You have to show me the selections so I can help you :)

Step-by-step explanation:

6 0
3 years ago
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(a) (4,4) is a point on a locus whose equation is y2 = kx. Show that (16,8) is another point on the locus.
Vlad [161]

Step-by-step explanation:

plug the coordinate points into the equations and solve for the remaining variable.

b) (2,3) - 5(2) + b(3) = 16

10 + 3b = 16. 3b= 6. b = 2

(0,8) - 5(0) + 2(8) = 16. 0+ 16 = 16. ☆

a) (4,4) assume based on results you meant y squared. (y^2)

(4)^2 = 4k. 16 = 4k. k = 4

(8)^2 = 4(16). 64 = 64. ☆

6 0
3 years ago
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How do you simplify expressions with rational exponents
Rainbow [258]

Answer:

Step-by-step explanation:

Simplify expression with rational exponents can look like a huge thing when you first see them with those fractions sitting up there in the exponent but let's remember our properties for dealing with exponents. We can apply those with fractions as well.

Examples

(a)   (p^4)^{\dfrac{3}{2}}

From above, we have a power to a power, so, we can think of multiplying the exponents.

i.e.

(p^{^ {\dfrac{4}{1}}})^{\dfrac{3}{2}}

(p^{^ {\dfrac{12}{2}}})

Let's recall that when we are dealing with exponents that are fractions, we can simplify them just like normal fractions.

SO;

(p^{^ {\dfrac{12}{2}}})

= (p^{ 6})

Let's take a look at another example

\Bigg (27x^{^\Big{6}} \Bigg) ^{{\dfrac{5}{3}}}

Here, we apply the \dfrac{5}{3} to both 27 and x^6

= \Bigg (27^{{\dfrac{5}{3}}} \times x^\Big{\dfrac{6}{1}\times {{\dfrac{5}{3}}} }\Bigg)

= \Bigg (27^{{\dfrac{5}{3}}} \times x^\Big{\dfrac{2}{1}\times {{\dfrac{5}{1}}} }\Bigg)

Let us recall that in the rational exponent, the denominator is the root and the numerator is the exponent of such a particular number.

∴

= \Bigg (\sqrt[3]{27}^{5} \times x^{10} }\Bigg)

= \Bigg (3^{5} \times x^{10} }\Bigg)

= 249x^{10}

8 0
3 years ago
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