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vichka [17]
2 years ago
6

What is the difference between adding whole numbers and adding decimals?

Mathematics
1 answer:
noname [10]2 years ago
4 0

Answer:

The only difference is that we line up the numbers according to the decimal point. For addition, it doesn't matter which number goes on the bottom.

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1. Round 47.38 to the nearest tenth.
attashe74 [19]

Answer:

1.  47.38

2.  6

3.  18.57

4.   114.9

5.   75.01

Step-by-step explanation:

6 0
3 years ago
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Two numbers are in the ratio 7:10 If the larger number is 140,what is the smaller number ​
nydimaria [60]

Given that nos. are in ratio 7:10

The larger no. is 140

Let the smaller no. be x

Using ratio and proportion

7 : 10 :: x : 140

⇒10 × x = 140 × 7

⇒x =  \frac{140 \times 7}{10}  = 98 \\

<em>-</em><em> </em><em>BRAINLIEST</em><em> ANSWERER</em>

3 0
3 years ago
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6x + 8y = 0<br> -48-8y=-8<br> A) (-4,-1)<br> C) No solution<br> B) (4,3)<br> D) (-4,3)
Marizza181 [45]

Answer:

CDF TIME` HEIGHT_A X HEIGHT_E , location Jeju longitude(degE) B ? latitude(degN) B (? altitude(m) % date 160216 lidar ratio(sr) 2 molecular backscatter(per msr) X5衭 ...

Step-by-step explanation:

CDF TIME` HEIGHT_A X HEIGHT_E , location Jeju longitude(degE) B ? latitude(degN) B (? altitude(m) % date 160216 lidar ratio(sr) 2 molecular backscatter(per msr) X5衭 ...

3 0
3 years ago
If 2x+7 over 4 =5, what is the value of 6x
jekas [21]

Answer:

(2x+7)/4=5

2x+7 = 20

2x= 20-7

2x = 13

x = 13/2

so

6x =13/2×6

=13×3

=39

4 0
3 years ago
A tractor, starting from a stationary position, drives down the road. It accelerates at 4 m/s2 for 10 seconds, then travels at a
chubhunter [2.5K]

Answer:

B. 1400 meters.

Step-by-step explanation:

According to the statement, there are two stages for the motion of the tractor, in which we need to find the travelled distance:

(i) <em>Uniform accelerated motion.</em>

<em />s_{i} = s_{o,i} +v_{o,i}\cdot t_{i} + \frac{1}{2}\cdot a\cdot t_{i}^{2}<em> </em>(1)

v_{i} = v_{o,i}+a\cdot t_{i} (2)

Where:

s_{o,i} - Initial position of the tractor, measured in meters.

s_{i} - Final position of the tractor, measured in meters.

v_{o,i} - Initial velocity of the tractor, measured in meters per second.

t_{i} - Time, measured in seconds.

a - Acceleration, measured in meters per square second.

v_{i} - Final velocity of the tractor, measured in meters per second.

(ii) <em>Uniform motion.</em>

s_{ii} = s_{i} + v_{i}\cdot t_{ii} (3)

Where:

s_{ii} - Final position of the tractor, measured in meters.

t_{ii} - Time, measured in seconds.

The distance covered by the tractor (\Delta s), measured in meters, is:

\Delta s = s_{ii} (4)

If we know that a = 4\,\frac{m}{s^{2}}, t_{i} = 10\,s, v_{o,i} = 0\,\frac{m}{s}, s_{o,i} = 0\,m and t_{ii} = 30\,s, then distance covered by the tractor is:

By (1) and (2):

s_{i} = 0\,m + \left(0\,\frac{m}{s} \right)\cdot (10\,s)+ \frac{1}{2}\cdot \left(4\,\frac{m}{s^{2}} \right) \cdot (10\,s)^{2}

s_{i} = 200\,m

v_{i} = \left(0\,\frac{m}{s} \right)+\left(4\,\frac{m}{s^{2}} \right)\cdot (10\,s)

v_{i} = 40\,\frac{m}{s}

By (3):

s_{ii} = 200\,m + \left(40\,\frac{m}{s} \right)\cdot (30\,s)

s_{ii} = 1400\,m

By (4):

\Delta s = 1400\,m

The correct answer is B.

4 0
3 years ago
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