3 years ago

Micaela is cooking bread. The recipe calls

Mathematics

1 answer:

Feliz [49]3 years ago

4 0

Answer:

1 and 5/10 or 1 and 1/2

Step-by-step explanation:

5 and 3/10 - 3 and 4/5 -

$\frac{53}{10}$ - $\frac{19}{5}$

= $\frac{15}{10}$

1 and 5/10 or 1 and 1/2

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Convert 6 and 3/5 to an improper fraction.

VikaD [51]

Answer: 33/5

Step-by-step explanation:

6 x 5 = 30

30 + 3 = 33

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4 years ago

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What are the zeros of the quadratic function f(x) = 6x ^ 2 - 24x + 1 ?

ZanzabumX [31]

Answer:

x = $\frac{12+\sqrt{138} }{6}$ and x = $\frac{12-\sqrt{138} }{6}$

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: $x=\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $x=\frac{-b-\sqrt{b^2-4ac} }{2a}$ .

Here, a = 6, b = -24, and c = 1. Plug these in:

$x=\frac{-b+\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}$

AND

$x=\frac{-b-\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}$

Thus, the zeroes are: x = $\frac{12+\sqrt{138} }{6}$ and x = $\frac{12-\sqrt{138} }{6}$ .

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3 years ago

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Replace the ___ with <, >, or = to make a true statement. 7^4/7^2(fraction) ___ 49

Brrunno [24]

Use this exponent property;
$\dfrac{a^m}{a^n} = a^{m-n}$

So you have $\dfrac{7^4}{7^2} =7^{4-2} = 7^2 = \boxed{49}$

So you should use " $=$ ".

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3 years ago

First to answer gets brainleist

Digiron [165]

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Step-by-step explanation:

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Identify the terms in the expression 8x + 6 + 2xy + z

tekilochka [14]

There are four terms: 8x, 6, 2xy, and z because they are being separated by addition or subtraction symbols. Hope this helps.

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