Answer:
The probability of of a randomly chosen student being exactly 21 years old.
= 1.293
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given Population size n = 500</em>
<em>Mean of the Population = 20 years and 6 months</em>
<em> = </em>
<em></em>
<em>Standard deviation of the Population = 2 years</em>
Let 'X' be the range of ages of the students on campus follows a normal distribution
Let x =21


<em>The probability of a randomly chosen student being exactly 21 years old.</em>
<em>P( Z≤21) = 0.5 + A( 0.2) </em>
= 0.5 +0.793
= 1.293
Answer:
11 dimes and 16 quarters
Step-by-step explanation:
system of equations lol
Answer:
The answer is D
Step-by-step explanation:
The answer is B because if you have 10000 hours you subtract by 3000 and it’s equals b
Answer:
C - 3,600
Step-by-step explanation:
100 16 45 ÷ 2
50. 8. 45 ÷ 2
25. 4. 45 ÷ 2
25. 2. 45. ÷ 2
25. 1. 45. ÷ 3
25. 1. 15. ÷ 3
25. 1. 5. ÷ 5
5. 1. 1. ÷ 5
1. 1. 1
L.C.M = 2 x 2 x 2 x 2 x 3 x 3 x 5 x 5 = 3, 600
I know this may be confusing but if you don't understand, you're welcome to ask.