Help needed ASAP will give BRAINLIEST AND 5 STARS RATE

67. The line contains the point (4,0) and is parallel to the line defined by 3x = 2y.

olganol [36]

Answer:

$y=\frac{3}{2} x-6$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form:

$y=mx+b$ where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)

Parallel lines will always have the same slope but different y-intercepts.

1) Determine the slope of the parallel line

Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

$3x = 2y$

Switch the sides

$2y=3x$

Divide both sides by 2 to isolate y

$\frac{2y}{2} = \frac{3}{2} x\\y=\frac{3}{2} x$

Now that this equation is in slope-intercept form, we can easily identify that $\frac{3}{2}$ is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope $\frac{3}{2}$ . Plug this into $y=mx+b$ :

$y=\frac{3}{2} x+b$

2) Determine the y-intercept

$y=\frac{3}{2} x+b$

Plug in the given point, (4,0)

$0=\frac{3}{2} (4)+b\\0=6+b$

Subtract both sides by 6

$0-6=6+b-6\\-6=b$

Therefore, -6 is the y-intercept of the line. Plug this into $y=\frac{3}{2} x+b$ as b:

$y=\frac{3}{2} x-6$

I hope this helps!

7 0

2 years ago

I WILL GAVE BRAINLIEST

Arte-miy333 [17]

Answer:

x < -14

Step-by-step explanation:

Step 1: Subtract 6 from both sides.

$-3x+6-6 > 48-6$
$-3x > 42$

Step 2: Divide both sides by -3 and flip the inequality sign.

$-3x/-3 > 42/-3$
$x < -14$

Therefore, the answer is x < -14.

4 0

2 years ago

Read 2 more answers

Select the decimal that is equivalent to 1/8

iogann1982 [59]

The answer is 0.125....................................

5 0

2 years ago

Read 2 more answers

Which points are the verticles of the ellipse? Equations of ellipse

Mashutka [201]

Answer:

This question is solved in detail below. Please refer to the attachment for better understanding of an Ellipse.

Step-by-step explanation:

In this question, there is a spelling mistake. This is vertices not verticles.

So, I have attached a diagram of an ellipse in which it is clearly mentioned where are the vertices of an ellipse.

Vertices of an Ellipse: There are two axes in any ellipse, one is called major axis and other is called minor axis. Where, minor is the shorter axis and major axis is the longer one. The places or points where major axis and minor axis ends are called the vertices of an ellipse. Please refer to the attachment for further clarification.

Equations of an ellipse in its standard form:

$\frac{x^{2} }{a^{2} } + \frac{y^{2} }{b^{2} } = 1$

This is the case when major axis the longer one is on the x-axis centered at an origin.

$\frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} } = 1$

This is the case when major axis the longer one is on the y-axis centered at an origin.

where major axis length = 2a

and minor axis length = 2b

3 0

2 years ago

What is the area, in square inches, of the isosceles trapezoid below?

zimovet [89]

Answer:

104.8 in^2

Step-by-step explanation:

There are 2 ways to solve this problem.

The 1st way:

Let's make 2 triangles and 1 rectangle:

Rectangle Length = 8.3

Rectangle Width = 8

So, the left out length will be 17.9 - 8.3

=> 9.6

Since, 9.6 cm is for 2 parts.

=> 9.6 / 2

=> 4.8

So, Height of the Triangle = 8

Base of the triangle = 4.8

Area of a rectangle

=> 8.3 x 8

=> 66.4

Area of the triangle

=> 1/2 x 8 x 4.8

=> 4 x 4.8

=> 19.2

There are 2 triangles:

=> 19.2 x 2

=> 38.4

=> 66.4 + 38.4

=> 104.8

The area of the trapezoid = 104.8 in^2.

The 2nd way is:

Area of a trapezoid

=> Smaller Base + Larger Base / 2 x Height

=> 8.3 + 17.9 / 2 x 8

=> 26.2 / 2 x 8

=> 13.1 x 8

=> 104.8

The area of the trapezoid is 104.8 in^2

6 0

3 years ago