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2 years ago

11

Select all the pairs that could be reasonable approximations for the diameter and circumference of a circle. Explain your reason

ing.
5 meters and 22 meters.

19 inches and 60 inches.

33 centimeters and 80 centimeters.

1 answer:

rosijanka [135]2 years ago

3 0

Answer:it’s 19 inches and 60 inches.

Step-by-step explanation:

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Can someone help me identify what quadrilateral is this?

photoshop1234 [79]

Answer:

Its C

Step-by-step explanation:

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3 years ago

What is the range of the function on the graph?

STALIN [3.7K]

Answer:

the answer is D. all real numbers greater than or equal to 2.

Step-by-step explanation:

looking at the graph, half of a parabola is curved upwards, and will never stop going up. looking at (1, 2), the dot (instead of circle) indicates the range is greater than or equal to itself, which is 2.

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3 years ago

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The rectangle is 20 by 16 and the scale factor is 0.25. What are the dimensions of the reduced rectangle?

antoniya [11.8K]

Answer:

1,280

The dimensions are 5 by 4

Step-by-step explanation:

You multiply 20 and 16 then, divide 0.25 then you get 1,280

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2 years ago

What five digit number am i thinking of? It has two prime digits. Digit three is the highest digit. Digit to is the lowest digit

Alexxx [7]

Answer:

47836

Step-by-step explanation:

1. Digit Three is the highest digit which is 8.

2. Digit two is the lowest digit which is 3.

3. Digit five is half of digit three and digit five is 4.

4. Digit one is smaller than digit 3 which is 6 and 8.

5. And we need a prime number for digit 4 which is 7.

Hope this helps.

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3 years ago

PLEASEEE HELP MEEEE<br><br>NO LINKSSS

Artemon [7]

Answer:

$\huge\boxed{(2,\ 3);\ (-1,\ 6)}$

Step-by-step explanation:

$f(x)=x^2-2x+3\to y=x^2-2x+3\\f(x)=-x+5\to y=-x+5\\\\\left\{\begin{array}{ccc}y=x^2-2x+3&(1)\\y=-x+5&(2)\end{array}\right$

substitute (1) to (2):

$x^2-2x+3=-x+5$ add x to both sides

$x^2-2x+x+3=-x+x+5$

$x^2-x+3=5$ subtract 5 from both sides

$x^2-x+3-5=5-5$

$x^2-x-2=0\\\\x^2+x-2x-2=0\\\\x(x+1)-2(x+1)=0\\\\(x+1)(x-2)=0\iff x+1=0\ \vee\ x-2=0\\\\\boxed{x=-1\ \vee\ x=2}$

substitute the values of x to (2):

$x=-1\\\\y=-(-1)+5=1+5=6\\\\\huge\boxed{(-1,\ 6)}\\\\x=2\\\\y=-2+5=3\\\\\huge\boxed{(2,\ 3)}$

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2 years ago