Answer:
6550
Step-by-step explanation:
You can put this solution on YOUR website!
Call the number of hardcover and paperback books, h and p.
Thus
h + p = 8 and the value equation is
4h + 2p = 26
Now multiply the top one by four and subtract from the second one...we get
4h + 2p = 26
-(4h + 4p = 32)
----------------
-2p = -6
p = 3 so that
h = 5 x + y = 8, (1)
4x + 2y = 26, (2)
where x and y are the numbers of hardcover and softcover books respectively.
To solve, multiply the equation (1) by 2 (both sides) and then distract it from the equation (2). You will get
4x - 2x = 26 - 16, or
2x = 10, or x = 5 - the number of hardcover books purchased.
Then from the equation (1) you get y = 3.
Check. 4*x + 2*3 = 4*5 + 2*3 = 26. OK.
Answer:
38 should be the right answer.
Step-by-step explanation:
Hope it helped and I also hope it is correct. :)
Let's call the number of student tickets they sold s, and the number of adult tickets they sold a.
The school sold 50 tickets in all, so a+s=50.
For every adult ticket they sold, they made $3, and for every student ticket, they made $2. So the total amount of money they made is 3a+2s. The problem tells us they made $135, so 3a+2s=135.
a + s = 50
3a + 2s = 135
This is a system of equations. We will proceed by changing the first equation, solving for a(we could solve for s instead, but I decided to solve for a). What this means is we will subtract s from both sides to get a alone.
a + s = 50
a = 50 - s
Now we know what a is(in terms of s, that is), so we can plug it into the second equation.
3a + 2s = 135
3(50 - s) + 2s = 135 (Remember to put the parentheses in!)
150 - 3s + 2s = 135
150 - s = 135
-s = -15
s = 15
This means 15 student tickets were sold. Plug this into one of the original equations to figure out how many adult tickets were sold:
a + s = 50
a + 15 = 50
a = 35
15 student tickets were sold, and 35 adult tickets were sold.
Answer:
20.8
Step-by-step explanation:
The chord with length x is bisected by the perpendicular segment.
Use the Pythagorean theorem to find the length of half of x.
Let's call half of x, y.
y^2 + 6^2 = 12^2
y^2 = 144 - 36
y^2 = 108
y = sqrt(108)
x = 2y = 2sqrt(108)
x = 20.8
I am sorry but I cannot see the two triangles
