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FrozenT [24]
3 years ago
8

Rena spent 6 days reading her book completing the same fraction of the book each day if she had a total of 8/9 of her book after

6 days what fraction of the book did she react each day
Mathematics
1 answer:
Artyom0805 [142]3 years ago
3 0

Answer:

The fraction of the book that Rena read every day is \frac{4}{27}

Step-by-step explanation:

Rena spent 6 days reading her book completing the same fraction of the book every day and you want to know the fraction of the book she read each day. Knowing that Rena had a total of 8/9 of her book read after 6 days, then you simply divide the total amount of the book read during those days by 6, the number of days:  

\frac{8}{9}÷6

To divide a fraction by a whole number, you must convert the whole number into a fraction, finding the reciprocal of that fraction, and multiply it by the first fraction. That is, you must find the reciprocal of the number that is after the division symbol; and then you multiply the first number (the one before the division symbol) by the reciprocal of the second number (the one after the division symbol). Remember that to find the reciprocal of a number, you simply have to change the numerator and denominator of the number.

Since 6 can be considered to be a fraction equal to \frac{6}{1}, by inverting the number, then you get \frac{1}{6}

Then:

\frac{8}{9}÷6= \frac{8}{9} *\frac{1}{6}

Now you multiply the numerators and denominators of the fraction to get the new numerator and denominator of the final solution.

\frac{8}{9}÷6= \frac{8}{9} *\frac{1}{6}=\frac{8*1}{9*6} =\frac{8}{54}

Finally, simplifying the fraction:

\frac{8}{9}÷6= \frac{8}{9} *\frac{1}{6}=\frac{8*1}{9*6} =\frac{8}{54}=\frac{4}{27}

So:

\frac{8}{9}÷6= \frac{4}{27}

<u><em>The fraction of the book that Rena read every day is </em></u>\frac{4}{27}<u><em></em></u>

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Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be
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Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of t=0.6482

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

h(t)=-16t^2 +v_{o}t+s       Eqn(1).

Where:

h(t) : is the height range as a function of time

v_{o}   : is the initial velocity

s     : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

h(t)=-16t^2 + v_{o}t + 40        Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

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We know that v_{o}=60ft/s

Thus Eqn. (2) becomes:

h(t)=-16t^2+60t+40        Eqn.(3)

<u>Josh:</u>

We know that v_{o}=48ft/s

Thus Eqn. (2) becomes:

h(t)=-16t^2+48t+40       Eqn. (4).

<em><u>Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at </u></em>h(t)=0<em><u>. Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one. </u></em>

Thus we have for Ben, Eqn. (3) gives:

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Similarly solving for Josh we obtain

t_{1}=3.6794sec\\t_{2}=-0.6794sec

Thus again we reject the negative and keep the positive solution, so Josh's book took t=3.6794 seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482

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<em>Whose textbook reaches the ground first and by how many seconds?</em>

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