Solution: (2,8)
Using the elimination method set up the system of equations like:
y = x + 6
y = 3x + 2
Eliminate the x-variable by multiplying the top equation by -3
-3y = -3x -18
y = 3x + 2
Combine terms:
-2y = -16
-y = -8
y = 8
Plug in 8 to one of the first equations for y
8 = 3x + 2
6 = 3x
x = 2
Solution: (2,8)
2x^-3= 2/x^3
you can't multiple 2x to the power of -3 because is not correct. so you need to change the equation for it to give you an answer
Answer:
<h3>perpendicular line:
y = -¹/₆
x + 4¹/₃
</h3><h3> parallel line:
y = 6x - 45
</h3>
Step-by-step explanation:
y=m₁x+b₁ ⊥ y=m₂x+b₂ ⇔ m₁×m₂ = -1
{Two lines are perpendicular if the product of theirs slopes is equal -1}
y = 6x - 7 ⇒ m₁=6
6×m₂ = -1 ⇒ m₂ = -¹/₆
The line y=-¹/₆
x+b passes through point (8, 3) so the equation:
3 = -¹/₆
×8 + b must be true
3 = -⁴/₃ + b
b = 4¹/₃
Therefore equation in slope-intercept form:
y = -¹/₆
x + 4¹/₃
y=m₁x+b₁ ║ y=m₂x+b₂ ⇔ m₁ = m₂
{Two lines are parallel if their slopes are equal}
y = 6x - 7 ⇒ m₁=6 ⇒ m₂=6
The line y=6x+b passes through point (8, 3) so the equation:
3 = 6×8 + b must be true
3 = 48 + b
b = -45
Therefore equation in slope-intercept form:
y = 6x - 45
My answer was wrong, please delete this
