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SIZIF [17.4K]
2 years ago
12

a window frame that uses a scale of 1 cm to 6 inches. Create another scale drawing of the same window using a scale of 1 cm to 1

2 inches. What is the length (top/bottom sides) of the window frame on your new scale drawing?
Mathematics
2 answers:
Nata [24]2 years ago
7 0

Answer:

Can you plz help me first

Step-by-step explanation:

Can you plz help me first

uranmaximum [27]2 years ago
3 0

Answer:

184

Step-by-step explanation:

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My last one got deleted but whats 10x5 i dont actually but u get it
andre [41]

Answer:

50 and 160

Step-by-step explanation:

good

6 0
2 years ago
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Please help me solve this problem with step by step explanation.​
Kisachek [45]

Answer:

Im not rally sure but maybe 5.71 , here is my explanation :

Step-by-step explanation:

Tan 55 =x/4

tan 55 = 1/42814

1/42814 = x /4

×=5.712592027 .

3 0
3 years ago
PLZ HELP ASAP!!!!!!!!!!!!!!!!!
eimsori [14]
B and C because both bases are squares
8 0
2 years ago
What is 3/18 divided by 7/21... help plz
saw5 [17]
3/18 divided 7/21 =3/18 multiply by 21/7 (we have to flip the second fraction and multiply by 3/18)= 63/126=1/2
So the answer is 1/2
8 0
3 years ago
Read 2 more answers
Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x
BaLLatris [955]

Answer:

The area of the region is 25,351 units^2.

Step-by-step explanation:

The Fundamental Theorem of Calculus:<em> if </em>f<em> is a continuous function on </em>[a,b]<em>, then</em>

                                   \int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) |  {_a^b}

where F is an antiderivative of f.

A function F is an antiderivative of the function f if

                                                    F^{'}(x)=f(x)

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x + 15 and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx

\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2

3 0
3 years ago
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