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3 years ago

Write 3200 as a product of prime factor

1 answer:

4 0

3200
32×100
8×4 × 10×10
4×2 × 2×2 × 5×2 × 5×2
2×2 × 2 × 2×2 × 5×2 × 5×2

so
2×2×2×2×2×2×2×5×5

or can be written as
2^7 × 5^2

hope it helps X

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WVXZ is a parallelogram. Given that <ZXV = 70° and <WZX =4y+34, find y and m<Z

rjkz [21]

Answer:

WZX = 110

y = 19

Step-by-step explanation:

We can create the following equation to solve for y.

$4y + 34 + 70 = 180$

Reduce

4y = 76

y = 19

We then plug into 4y + 34 to get angle

WZX = 110

5 0

2 years ago

Explain how you could use a number line to show that -4+3 and 3+(-4) have the same value.which property of addition states that

Anna007 [38]

For -4+3,
1. start with zero
2. move to left (-x axis) for 4 units (-4)
3. then move to right (+x axis) for 3 units (+3)

For 3+(-4)
1. Start with zero
2. Move the point to right side by 3 units (+3)
3. then move the point to the left by 4 units (-4)

For both you'll stop at -1.

8 0

3 years ago

How do I do this?? Help!

Shkiper50 [21]

Hi there!

In order to use the elimination method, you have to create one variable that has the same coefficient. This is to be able to eliminate one variable and have a one variable equation (which you can then solve).

In your case, we'll have the "x" have the same coefficient by multiplying the top equation by 4 and the bottom equation by 2 :

4( -2x + 3y = -4) → -8x + 12y = -16

2( 4x - 2y = 16) → 8x - 4y = 32

Now that both of your equation have a variable with the same coefficient, you need to choose rather you need to add or subtract the equations in order to get rid of the variable (in this case we want to get rid of the "x").

In your case, you want to add both equation together which will give you :

8y = 16

Now that you only have one variable, all you need to do now is solve the equation for "y" :

8y = 16

Divide each side of the equation by 8

y = 2 → Your answer

There you go! I really hope this helped, if there's anything just let me know! :)

7 0

3 years ago

Read 2 more answers

I already solved this problem. I just need help with the HINT part.

frutty [35]

$x+y=25 \\ y=25-x~~Other~number~in~terms~of~x \\ \\ x^2+y^2=313 \\ x^2+2xy+y^2=313+2xy \\ (x+y)^2=313+2x(25-x) \\ \frac{25^2-313}{2} =25x-x^2 \\ x^2-25x+156 \\ \\ \Delta =(-25)^2-4\times 1\times 156 \\ \Delta =625-624 \\ \sqrt{\Delta}=1 \\ \\ x= \frac{25 \pm 1}{2} \\ x= \left \{ {{x_1=13} \atop {x_2=12}} \right.$

The number "x" is given by:
$y= \left \{ {{y_1=25-13 \rightarrow~y_1=12} \atop {y_1=25-12 \rightarrow ~y_1=13}} \right.$

Therefore, we have:

$\boxed {S=({12,13})} \rightarrow~The~curly~braces~does~not~want~appear~here.$

8 0

3 years ago

Help asap plsss ..lol

coldgirl [10]

Answer:

n = 3/7

Step-by-step explanation:

8 0

3 years ago