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Alecsey [184]
3 years ago
9

How do you know if the price of a particular house fits your budget?

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
7 0
You would be able to afford it. It would be he same price or below you budget.
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2. Sophia scored 42 points in 3 games. How many points would you expect her to make in 11 games?​
igomit [66]

Answer:

154

Step-by-step explanation:

42/3=14

14*11=154

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2 years ago
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Complete the table 3 5 8 ? 12
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4 is the answer........
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3 years ago
Which table of ordered pairs represents a proportional relationship?
Shkiper50 [21]

Answer:5

Step-by-step explanation:

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3 years ago
If 20% of the people in a community use the emergency room at a hospital in one year, find
Pie

Answer:

a) 87.91% probability that at most three used the emergency room

b) 20.13% probability that exactly three used the emergency room.

c) 3.28% probability that at least five used the emergency room​

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they use the emergency room, or they do not. The probability of a person using the emergency room is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Sample of 10 people:

This means that n = 10

20% of the people in a community use the emergency room at a hospital in one year

This means that p = 0.2

a) At most three used the emergency room

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074

P(X = 1) = C_{10,1}.(0.2)^{1}.(0.8)^{9} = 0.2684

P(X = 2) = C_{10,2}.(0.2)^{2}.(0.8)^{8} = 0.3020

P(X = 3) = C_{10,3}.(0.2)^{3}.(0.8)^{7} = 0.2013

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.1074 + 0.2684 + 0.3020 + 0.2013 = 0.8791

87.91% probability that at most three used the emergency room

b) Exactly three used the emergency room

P(X = 3) = C_{10,3}.(0.2)^{3}.(0.8)^{7} = 0.2013

20.13% probability that exactly three used the emergency room.

c) At least five used the emergency room​

P(X \geq 5) = 1 - P(X < 5)

In which

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

From 0 to 3, we already have in a).

P(X = 4) = C_{10,4}.(0.2)^{4}.(0.8)^{6} = 0.0881

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.1074 + 0.2684 + 0.3020 + 0.2013 + 0.0881 = 0.9672

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.9672 = 0.0328

3.28% probability that at least five used the emergency room​

4 0
3 years ago
What is the difference between -5 and 2?
swat32

Answer:

2 is the bigger number

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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