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Alecsey [184]
3 years ago
9

How do you know if the price of a particular house fits your budget?

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
7 0
You would be able to afford it. It would be he same price or below you budget.
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In the figure below, Z is the center of the circle. Suppose that OR=4, ST= 4, UZ= 6, and VZ=4x-6. Find the following.
Ann [662]

Answer:

x = 3 units

SV = 2 units

Step-by-step explanation:

In\odot Z QR and ST are chords such that:

QR = ST = 4

That is both the chords are equal in measure.

Equal chords are at equal distance from the center of the circle. Therefore,

VZ = UZ

4x - 6 = 6

4x = 6 + 6

4x = 12

x = 12/4

x = 3 units

Since, perpendicular dropped from the center of the circle bisects the chord.

\therefore SV = \frac{1}{2} ST

\therefore SV = \frac{1}{2} \times 4

\therefore SV = 2\: units

3 0
3 years ago
In a shipment of new books for the library,5/12 of the books were poetry and 2/5 were biographies. The remainder of the books in
mr Goodwill [35]
5/12(poetry) + 2/5(biographies) = 25/60 + 24/60 = 49/60
60/60 - 49/60= 11/60
11/60 are the remainder of the books in the shipment.
3 0
3 years ago
Which is a true statement about 7 and 14?
Ksju [112]
7 and 14 can be divided in to two
7 0
4 years ago
If two lines are perpendicular, which statement must be true? A.The slopes of the two lines are equal. B.The slopes of the two l
dangina [55]

Answer:

Option D is correct that is The Slopes of two lines are negative reciprocals.

Step-by-step explanation:

Perpendicular lines are the lines which intersect each other at right angle or make 90° angle with each other.

we that the Slope of perpendicular lines are equal to -1

Therefore, Option D is correct that is The Slopes of two lines are negative reciprocals.

5 0
3 years ago
Complete the equation of the graphed linear function in point-slope form.
vazorg [7]
The point-slope form:
y-y_1=m(x-x_1)
m - slope
x₁, y₁ - the coordinates of a point

It passes through the points (1,-2) and (2,2).
(1,-2) \\
x_1=1 \\ y_1=-2 \\ \\
(2,2) \\
x_2=2 \\ y_2=2 \\ \\
m=\frac{y_2-y_1}{x_2-x_1}=\frac{2-(-2)}{2-1}=\frac{2+2}{1}=4

\boxed{y-(-2)=4(x-1)}
3 0
3 years ago
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