Answer:
α = 62°
β = 56°
gamma = 90°
Step-by-step explanation:
ΔAOB is isosceles, so m∠A = m∠ABO = 28
28 + 28 + m∠AOB = 180
m∠AOB = 180 - 28 - 28 = 124
β = 180 - 124 = 56
arcAB = 124
ΔBOC is isosceles. α = m∠BCO = 1/2(arc AB) = 1/2(124) = 62
∠D is inscribed in a semicircle
m∠D = gamma = 90°
Answer:
x = 2* pi* n
Step-by-step explanation:
cos(2x) cos(x) + sin(2x) sin x =1
We know cos(s) cos(t) + sin(s) sin(t) = cos(s - t)
Using s =2x and t = x
cos (2x-x) =1
cos (x) =1
We know this occurs at 0, 2pi, 4 pi etc
x = 2* pi* n where n is an integer
Using the information given, it is found that the class width for this frequency distribution table is of 1.
In this problem, these following classes are given:
0 – 1 14
2 – 3 1
4 – 5 8
6 – 7 12
8 – 9 12
The classes not given, which are 1 - 2, 3 - 4 and 5 - 6, have values of 0.
The <u>difference between the bounds of the classes is of 1</u>, thus, the class width is of 1.
A similar problem is given at brainly.com/question/24701109
Step-by-step explanation:
The ratio of Ali mass to Williams mass is
6 : 3
= 2 : 1
Option 2 is the correct answer
