Distance from focus to vertex=distance from vertex to directix
from (6,2) to y=1, the distance is 1
the focus is 1/2 higher than the vertex
vertex=(6,1.5)
for
(x-h)^2=4p(y-k)
vertex=(h,k)
p=distance from vertex to directix
vertex=(6,1.5)
ditance=0.5
(x-6)^2=4(0.5)(y-1.5)
(x-6)^2=2(y-1.5) is the equation
or
y=0.5x^2-6x+19.5 or
y=0.5(x-6)^2+1.5
Answer:
18x^2 - 9
Step-by-step explanation:
y = f(x)= 6x^3 - 9x + 4
dy/dx = d/dx(6x^3) - d/dx(9x) + d/dx (4)
=6.d/dx(x^3) - 9.d/dx (x) + d/dx. (4)
=6.3x^2 - 9.1 + 0 =18x^2 - 9
1) 38cm
2) 2304cm^2
3) 64cm^2
To find the area you multiply the sides
To find the perimeter you add the sides
He would donate approximately 11 books a month <span />
721% is the right answer.
