Question

Please help......................,​

Answer 1

Answer:

Explanation:

in all the question we have to use same technique

in 1 question

weight/force exerted by dorje(F)=1500N

total surface area of sole(A)=0.5m²

we know that,

   P=$\frac{F}{A}$

or, p=$\frac{1500}{0.5}$

∴ P=3000pa

in question 2nd

pressure(P)=40 pa

force exerted by block(F)=80N

we know,

pressure(P)=$\frac{Force(F)}{Area(a)}$

   area=$\frac{80}{40}$

∴area =2m

ow you can do other by yourself