Answer:i think it would most likely be c
Step-by-step explanation:
since you can only add denominators when they are the same number
Step-by-step explanation:
37x + 41y = 70 --- R¹
41x + 37y = 86 --- R²
R¹ + R² : 78x + 78y = 156
78(x + y) = 156
x + y = 2 --- R³
R¹ - R² : -4x + 4y = -16
4(y - x) = -16
y - x = -4 --- R⁴
R³ + R⁴ : 2y = -2
y = -1
R³ - R⁴ : -2x = -6
x = 3
Answer:
minimum of 13 chairs must be sold to reach a target of $6500
and a max of 20 chairs can be solved.
Step-by-step explanation:
Given that:
Price of chair = $150
Price of table = $400
Let the number of chairs be denoted by c and tables by t,
According to given condition:
t + c = 30 ----------- eq1
t(150) + c(400) = 6500 ------ eq2
Given that:
10 tables were sold so:
t = 10
Putting in eq1
c = 20 (max)
As the minimum target is $6500 so from eq2
10(150) + 400c = 6500
400c = 6500 - 1500
400c = 5000
c = 5000/400
c = 12.5
by rounding off
c = 13
So a minimum of 13 chairs must be sold to reach a target of $6500
i hope it will help you!
The volume of one pan is 192 units cubed. The volume of the three pans is 576 units cubed.
