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julsineya [31]
4 years ago
14

What is the length of PQ¯¯¯¯¯?

Mathematics
2 answers:
timofeeve [1]4 years ago
5 0
Since you don't have any angle and its opposite side, you cannot establish the ratio for the law of sines, so you must use the law of cosines.

c^2 = a^2 + b^2 - 2ac \cos C

Let's change it for this problem.

r^2 = p^2 + q^2 - 2pq \cos R

r^2 = 9^2 + 6^2 - 2(9)(6) \cos 34^\circ

r^2 = 9^2 + 6^2 - 2(9)(6) \cos 34^\circ

r^2 = 27.46

r = 5.24

PQ = 5.2~km
serg [7]4 years ago
3 0

Answer:

Hello! The correct answer is 5.2 km

Step-by-step explanation:

I am just confirming!

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Using the point (3,1) and a slope of 3,
Mariulka [41]

Answer:

y= -1= 3(x -3)

Step-by-step explanation:

y -y1= m(x -x1)

y -1= 3(x -3)

8 0
2 years ago
Can I get some help on this pls
defon
2.) 3
3.) 3723
4.) 1512
5.)4692
6.)5525
7.) 760
8.) 696
6 0
3 years ago
Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.
gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant  is  mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is  mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)

The partial derivatives of a function are f x and f y.

\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\

&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}

In conclusion,  the area is

A=3 √4 units ^2

Read more about the plane

brainly.com/question/1962726

#SPJ4

5 0
1 year ago
Write the following as a root in radical form 2^-4/5
erastovalidia [21]

Answer:

Given that:

=2^(-4/5)

This means that 2 is the base and -4/5 is the exponent.

To change it in radical form:

  • firstly the denominator would be written with radical sign
  • Then the negative sign with 4 will be removed by inverting the base.
  • Then the fraction will be simplified according to the exponent (power)
  • All the steps are performed below:

=\sqrt[5]{2^{-4} } \\=\sqrt[5]{1/2^4}\\ =\sqrt[5]{1/16}

i hope it will help you!

6 0
3 years ago
What fractions are equivalent to 2/3
just olya [345]
4/6
10/15
6/9
8/12
Hope these help you!!! =')
4 0
4 years ago
Read 2 more answers
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