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3 years ago

Please help! And 20 points! :3 I need help with these 3 questions- -3-||

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

8 0

Answer:

18. Its 2 meters.

19. Its 0.2 grams

20. Its 1,920

Step-by-step explanation:

When you convert 200 centimeters to meters its 2.

When you convert 2,000 milligrams in grams its 0.2

15% of 12, 800 is 1,920

Hope this helps:)

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Where do I plot the points based on this graph

Goshia [24]

Answer:

You plot the points on the coordinates of [3, 0], [-1, 0], [-3, 0].

Step-by-step explanation:

You set the whole thing equal to zero, and when evaluated correctly, you come up with the above answer.

I am joyous to assist you anytime.

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3 years ago

-1/2(3x-4)+3x=5/6<br> Please help

Ksenya-84 [330]

Answer:

x = -7/9

Step-by-step explanation:

The usual recommendation is to clear fractions first. Here, you can do that by multiplying both sides of the equation by 6.

6(-1/2(3x -4) +3x) = 6(5/6)

-9x +12 +18x = 5 . . . . . . . . . simplify

9x = -7 . . . . . . . . . . . . . . . . . subtract 12

x = -7/9 . . . . . .divide by 9

Another way to do this is to eliminate parentheses first.

-3/2x +2 +3x = 5/6

3/2x = -7/6 . . . . . . . . . collect terms, subtract 2

x = (-7/6)(2/3) = -7/9 . . . . multiply by 2/3

3 0

3 years ago

Gina looks at the architectural plan of a four-walled room in which the walls meet each other at right angles. The length of one

soldier1979 [14.2K]

Answer:

For a better understanding of the solution provided here, please find the diagram attached.

In the diagram, ABCD is the room.

AC is the diagonal whose length is 18.79 inches.

The length of wall AB is 17 inches.

From the given information, we have to determine the length of the BC, which is depicted a , because for the room to be a square, the length of the wall AB must be equal to the length of the wall BC.

Thus, inches

and hence, the given room is not a square.

Step-by-step explanation:

6 0

3 years ago

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$

so, $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

since $\sqrt{3}=1.732$

so, $(6+7(1.732),0)\text{ and }(6-7(1.732),0)$ are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

3 0

3 years ago

Solve the system of equations - 3x + y = 7 and 9x – 6y = 3 by combining the<br> equations.

aniked [119]

(-5, -8)
(x, y)
would be your answer

3 0

3 years ago